Answer:
J: x - 2y = -8
Step-by-step explanation:
All you have to do is plug in x or y as 0 for the y-intercept and the x-intercept, respectively. But, for these specific equations, looking at the constant when y isn't multiplied by any number but 1 will show the y-intercept. (e.g. 2x + y = -12, -12 is the y-intercept, 2x - y = -20 -> -2x + y = 20, 20 is the y-intercept)
F: y-intercept = -12 (incorrect)
G: y-intercept = 0 (incorrect)
H: y-intercept = 20 (incorrect)
J: y-intercept = 4 (correct)
Answer:
47.4 ;
50
Step-by-step explanation:
Given the data :
X ($) : 85 139 161 175 85 133 149 145 136 131 290 235 132 149 322 214 105 90 162 229 121 113 149 126139 118 156 214 172 87 172 230 195 126 128 142 118 139
The smallest class interval :
Range / number of classes
Number of classes to use = 5
Range = Maximum - Minimum = (322 - 85) =237
Hence, smallest class interval :
237 / 5 = 47.4
A better class interval would be, one without decimal, rounded to the nearest 10; this will be easier and make more statistical sense
Hence, smallest class interval rounded to the nearest 10 :
47.4 = 50 (nearest 10)
Answer:
29.7
Step-by-step explanation:
The remaining distance is the total distance less the distance driven so far:
... 236.5 -69.4 -67.9 -69.5 = 29.7
Answer:
6.28
Step-by-step explanation:
2 x 3.14
Answer:
Hence after 3.98 sec i.e 4 sec Object will hit the ground .
Step-by-step explanation:
Given:
Height= 6 feet
Angle =28 degrees.
V=133 ft/sec
To Find:
Time in seconds after which it will hit the ground?
Solution:
<em>This problem is related to projectile motion for objec</em>t
First calculate the Range for object and it is given by ,
(2Ф)/
Here R= range g= acceleration due to gravity =9.8 m/sec^2
1m =3.2 feet
So 9.8 m, equals to 9.8 *3.2=31.36 ft
So g=31.36 ft/sec^2. and 2Ф=2(28)=56
fts
Now using Formula for time and range as
Vx is horizontal velocity
Ф
(28)
ft/sec
So above equation becomes as ,
T is approximately equals to 4 sec.
