Each side of a box is s = 2.5 units
volume of one box is length * breadth * height
since its a cube all sides are equal
volume of one box = s³ = 2.5³
since there are 4 boxes,
total volume V = 4s³
V = 4 * 2.5³ = 4 * 15.625
= 62.50 cubic units
third response is correct
Answer:
Each student gets 11 pieces.
Step-by-step explanation:
80 ÷ 7 = 11.42857
80 divided by 7 comes out to a decimal therefore, you will have a remainder. 7 × 11 = 77
The answer would be 11 remainder 3.
Compacted u still have time tho don’t worry
Hello there.
<span>The area of the triangle shown below is 60 cm2. Find the value of x.
</span><span>36
</span>
first off, we know this equation is a quadratic equation, so it is of the form y = ax² + bx + c, where "a, b and c" are digits or constants, and we have no clue what they are.
well, let's take a peek at the table of values and let's make, hmmm usually we'd end up with a system of equations of 3 variables, but in this case we can cook it earlier by being wimpy and using the (0 , 0) point from the table, that says that y = 0 and x = 0, then we'll be using the point (-2 , 0), again being wimpy for the 0 and we know that y = 0 whilst x = -2.
![y = ax^2+bx+c \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{using (0 , 0)}}{0 = a(0)^2+b(0)+c}\implies \boxed{0=c} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{using (-2 , 0)}}{0=a(-2)^2+b(-2)+0}\implies 0=4a-2b\implies 2b=4a \\\\\\ \cfrac{2b}{2}=2a\implies \underline{b=2a} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{using (2 , 4)}}{4=a(2)^2+b(2)+0}\implies 4=4a+2b\implies \stackrel{\textit{substituting 2b}}{4=4a+2(2a)} \\\\\\ 4=4a+4a\implies 4=8a\implies \cfrac{4}{8}=a\implies \boxed{\cfrac{1}{2}=a}](https://tex.z-dn.net/?f=y%20%3D%20ax%5E2%2Bbx%2Bc%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Busing%20%280%20%2C%200%29%7D%7D%7B0%20%3D%20a%280%29%5E2%2Bb%280%29%2Bc%7D%5Cimplies%20%5Cboxed%7B0%3Dc%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Busing%20%28-2%20%2C%200%29%7D%7D%7B0%3Da%28-2%29%5E2%2Bb%28-2%29%2B0%7D%5Cimplies%200%3D4a-2b%5Cimplies%202b%3D4a%20%5C%5C%5C%5C%5C%5C%20%5Ccfrac%7B2b%7D%7B2%7D%3D2a%5Cimplies%20%5Cunderline%7Bb%3D2a%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Busing%20%282%20%2C%204%29%7D%7D%7B4%3Da%282%29%5E2%2Bb%282%29%2B0%7D%5Cimplies%204%3D4a%2B2b%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bsubstituting%202b%7D%7D%7B4%3D4a%2B2%282a%29%7D%20%5C%5C%5C%5C%5C%5C%204%3D4a%2B4a%5Cimplies%204%3D8a%5Cimplies%20%5Ccfrac%7B4%7D%7B8%7D%3Da%5Cimplies%20%5Cboxed%7B%5Ccfrac%7B1%7D%7B2%7D%3Da%7D)
![~\dotfill\\\\ \stackrel{\textit{we know that}}{b=2a}\implies b=2\left( \cfrac{1}{2} \right)\implies \boxed{b=1} \\\\[-0.35em] ~\dotfill\\\\ y=\cfrac{1}{2}x^2+1x+0\implies \boxed{y=\cfrac{1}{2}x^2+x} \\\\[-0.35em] ~\dotfill\\\\ \textit{when x = 4, what's "y"?}\qquad y=\cfrac{1}{2}(4)^2+4\implies y=\cfrac{16}{2}+4\implies y=12](https://tex.z-dn.net/?f=~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bwe%20know%20that%7D%7D%7Bb%3D2a%7D%5Cimplies%20b%3D2%5Cleft%28%20%5Ccfrac%7B1%7D%7B2%7D%20%5Cright%29%5Cimplies%20%5Cboxed%7Bb%3D1%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20y%3D%5Ccfrac%7B1%7D%7B2%7Dx%5E2%2B1x%2B0%5Cimplies%20%5Cboxed%7By%3D%5Ccfrac%7B1%7D%7B2%7Dx%5E2%2Bx%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ctextit%7Bwhen%20x%20%3D%204%2C%20what%27s%20%22y%22%3F%7D%5Cqquad%20y%3D%5Ccfrac%7B1%7D%7B2%7D%284%29%5E2%2B4%5Cimplies%20y%3D%5Ccfrac%7B16%7D%7B2%7D%2B4%5Cimplies%20y%3D12)