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3 years ago

Please answer I’ll pay you $100 lol thanks

Mathematics

1 answer:

Nesterboy [21]3 years ago

4 0

Answer:

d = $\pi$

e = $-\sqrt{8}$

f = $\frac{3}{2}$

Step-by-step explanation:

D is equal to pi because pi is 3.1415... Therefore we need a point that is a little more than -3 and that is point d.

$-\sqrt{8}$ is roughly equal to -2.8 because 3 * 3 = 9 so that is too much, and 2 * 2 = 4 is too little so it has to be between -2 and -3. Therefore the point is e.

For 3/2 it has to be less than 2 because 2 cannot go into 3 more than once. The point would then be point f.

Hope this helps!!

- Kay :)

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Draw a model. Then, write the numerical expressions.

kondor19780726 [428]

Answer with Step-by-step explanation:

a. The difference between 8 forty-sevens and 7 forty-sevens

Let ⊕ repesents forty- sevens.

So, Model can be represented by

8⊕ - 7⊕

=⊕⊕⊕⊕⊕⊕⊕⊕-⊕⊕⊕⊕⊕⊕⊕

=⊕

Mathematically,

let x represents forty-sevens.

So, it becomes

$8x-7x=x$

b. 6 times the sum of 12 and 8.

Mathematically, it is expressed as

$6\times (12+8)\\\\=6\times 20\\\\=120$

Let 12 be written as 4×3

and 8 be written as 4×2

Let ⊕ represents 4 i.e. fours.

so, there are sum of 2 fours and 3 fours.

So, it becomes,

6×(⊕⊕+⊕⊕⊕)

=6×(⊕⊕⊕⊕⊕)

=⊕⊕⊕⊕⊕⊕⊕⊕⊕⊕⊕⊕⊕⊕⊕⊕⊕⊕⊕⊕⊕⊕⊕⊕⊕⊕⊕⊕⊕

=4×30

=120

3 0

3 years ago

A survey was sent out to compare the proportion of adults who use their car horns when driving for two age populations (1=younge

erastovalidia [21]

Answer:

The 90% confidence interval for the difference between proportions is (0.115, 0.228).

As the value 0 is not included in the interval, we can conclude that there is significant difference in the proportion of youger adults that use the horn and older adults that use the horn.

Step-by-step explanation:

We want to calculate the bounds of a 90% confidence interval.

For a 90% CI, the critical value for z is z=1.645.

The sample 1 (younger adults) , of size n1=501 has a proportion of p1=0.521.

$p_1=X_1/n_1=261/501=0.5210$

The sample 2 (older adults), of size n2=352 has a proportion of p2=0.3494.

$p_2=X_2/n_2=123/352=0.3494$

The difference between proportions is (p1-p2)=0.1715.

$p_d=p_1-p_2=0.5210-0.3494=0.1715$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{261+123}{501+352}=\dfrac{384}{853}=0.4502$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.4502*0.5498}{501}+\dfrac{0.4502*0.5498}{352}}\\\\\\s_{p1-p2}=\sqrt{0.0005+0.0007}=\sqrt{0.0012}=0.0346$