The range of a function is the set of y-coordinates of all the points int he graph of the function.
Look at the graph. The vertex is point (2, -3).
The graph does not go lower than that point.
The lowest y-coordinate is -3.
The graph goes up forever on both sides until infinity.
The range is all numbers greater than or equal to -3.
The would be even and I assume you have the answer
6) arc length = 2*PI*R* degree/360
arc length = 2 * PI * 3 * 65/360
= 6*PI x 65/360
= 13/12*PI
Answer = C
7) drawing the lines as given would make a T shape with B being the mid point, so the answer would be C
I FOUND YOUR COMPLETE QUESTION IN OTHER SOURCES.
SEE ATTACHED IMAGE.
Using Heron's Formula we can find the area of the triangle.
A = root (s (s-a) * (s-b) * (s-c))
s = (a + b + c) / 2
Where,
s: semi-perimeter
a, b, c: sides of the triangle
Substituting values:
s = (15 + 16 + 20) / 2
s = 25.5
s = 26
The area will be:
A = root (26 * (26-15) * (26-16) * (26-20))
A = 130.9961832
A = 130 u ^ 2
Answer:
The area of triangle ABC is:
C.
130 u ^ 2
Answer:
-1152
Step-by-step explanation:
abc² the expression can be rewritten using the given values for each letter
(-3)*6*(-8)^2 now we find the second power of (-8) by multiplying it with itself
(-8)*(-8) = 64
(-3)*6*64 = -1152