Answer:
Hence proved △ABE∼△CBF.
Step-by-step explanation:
Given,
ABCD is a parallelogram.
BF ⊥ CD and
BE ⊥ AD
To Prove : △ABE∼△CBF
We have drawn the diagram for your reference.
Proof:
Since ABCD is a parallelogram,
So according to the property of parallelogram opposite angles are equal in measure.
⇒1
And given that BF ⊥ CD and BE ⊥ AD.
So we can say that;
⇒2
Now In △ABE and △CBF
∠A = ∠C (from 1)
∠E = ∠F (from 2)
So by A.A. similarity postulate;
△ABE∼△CBF
Answer:
b equals T minus a minus c minus d all over 3 ⇒ 3rd answer
Step-by-step explanation:
* Lets explain how to solve the problem
- Tisha and her academic team have had three local matches
# Assume that the points of the local matches are a , c , d
- They will attend a district match
- District match points count for three times the number of points
than local matches do
# Assume that the points of the district match is b
- T is the total points they will earned in the four matches
∵ The points in the local matches are a , c , d
∵ The point in district mach is 3b
∴ T = a + c + d + 3b
* <u><em>Lets find b in terms of a , c , d , T</em></u>
∵ T = a + c + d + 3b
- Subtract a from both sides
∴ T - a = c + d + 3b
- Subtract c from both sides
∴ T - a - c = d + 3b
- Subtract d from both sides
∴ T - a - c - d = 3b
- Divide both sides by 3
∴
∴ b equals T minus a minus c minus d all over 3