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Dima020 [189]
3 years ago
15

(9x – 9) (3x + 9)°/B Find the measure of ABC

Mathematics
1 answer:
katrin2010 [14]3 years ago
5 0

Answer:

<ABC = 54 degrees

Step-by-step explanation:

Taking the sum of angle on the straight line ABD as 180 degrees

3x+9 + 9x - 9 =180

12x = 180

x = 180/12

x =  15 degrees

Since <ABC = 3x+9 (vertically opposite angles)

<ABC = 3(15)+9

<ABC = 45+9

<ABC = 54 degrees

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3 years ago
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nekit [7.7K]

Recall the angle sum identities:

\sin(x+y)=\sin x\cos y+\cos x\sin y

\cos(x+y)=\cos x\cos y-\sin x\sin y

Now,

\tan(x+y)=\dfrac{\sin(x+y)}{\cos(x+y)}=\dfrac{\sin x\cos y+\cos x\sin y}{\cos x\cos y-\sin x\sin y}

Divide through numerator and denominator by \cos x\cos y to get

\tan(x+y)=\dfrac{\tan x+\tan y}{1-\tan x\tan y}

Next, we use the fact that x,y lie in the first quadrant to determine that

\sin x=\dfrac12\implies\cos x=\sqrt{1-\sin^2x}=\dfrac{\sqrt3}2

\cos y=\dfrac{\sqrt2}2\implies\sin x=\sqrt{1-\cos^2x}=\dfrac1{\sqrt2}

So we then have

\tan x=\dfrac{\sin x}{\cos x}=\dfrac{\frac12}{\frac{\sqrt3}2}=\dfrac1{\sqrt3}

\tan y=\dfrac{\sin y}{\cos y}=\dfrac{\frac1{\sqrt2}}{\frac{\sqrt2}2}=1

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4 0
3 years ago
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sub 2 for any "x"

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Answer:

Simple! She earned $280

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