Answer:
<h2>
</h2>
Step-by-step explanation:
<h3>to understand this</h3><h3>you need to know about</h3>
- area of triangles
- area of rectangle
- PEMDAS
<h3>tips and formulas:</h3>
- rectangle opposite sides are equal
- area of rectangle:l×w
- area of triangle:½×h×b
<h3>let's solve:</h3>
the area of the rectangle is
4×7 in²
28 in²
the area of above triangle is
½×6×7 in²
3×7 in²
21 in²
the area of left side triangle is
½×5×4 in²
2×5 in²
10 in²
therefore,
the area of the polygon is
28+21+10 in²
<h3>59 in²</h3>
The answer is B.) 1/4 because it goes 1 up and 4 right.
Using it's concept, it is found that the approximate perimeter of the front of the garage is:
A. about 36 ft.
<h3>What is the perimeter of a figure?</h3>
The perimeter of a figure is given by the total length of it's boundary.
In this problem, we have that:
- The bottom boundary has length of 10 units.
- The two lateral boundaries have lengths of 7 units.
- There are two top boundaries, which are the hypotenuses of a right triangle with legs 3 and 5, hence:
Hence the perimeter of the figure is:
P = 10 + 2 x 7 + 2 x 5.83 = 35.66.
Rounding, it is of about 36 ft, hence option A is correct.
More can be learned about the perimeter of a figure at brainly.com/question/26134384
#SPJ1
-6(a+8)
= (-6)(a+8)
= (-6)(a)+(-6)(8)
Your final answer would be -6a - 48!
