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2 years ago

Tommy can lay a brick walkway by himself in 12 hours. Robert does the same job in 10 hours.

Mathematics

1 answer:

Lapatulllka [165]2 years ago

8 0

Answer:

5 5/11 hours

Step-by-step explanation:

So, there is a trick to doing this.

You would first need to get their work rate into the same measurements.

That's why we will find out how much they each work in one hour.

Tommy does 1/12 of the work in one hour while Robert does 1/10.

Here we can add them both up to make 11/60.

They finish 11/60 of the work in one hour.

They finish the job in 5 5/11 hours.

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Samuel wants to eat at least 15 grams of protein each day. Let x represent the amount of protein he should eat each day to meet

MrRissso [65]

Answer:

X is greater than or equal to 15

Step-by-step explanation:

6 0

3 years ago

Mrs. Haley baked apple pies for her family. The boys ate 9/10 of a pie and the girls ate 2/5 of a pie. How much more pie did the

garik1379 [7]

Answer: The boys ate half a pie more than the girls did (5/10 more).

Step-by-step explanation:

2/5 = 4/10

The difference between 9/10 and 4/10 is 5/10, or one half, so that's your answer.

4 0

3 years ago

Consider two independent tosses of a fair coin. Let A be the event that the first toss results in heads, let B be the event that

aliina [53]

Answer with Step-by-step explanation:

We are given that two independent tosses of a fair coin.

Sample space={HH,HT,TH,TT}

We have to find that A, B and C are pairwise independent.

According to question

A={HH,HT}

B={HH,TH}

C={TT,HH}

$A\cap B=$ {HH}

$B\cap C$ ={HH}

$A\cap C$ ={HH}

P(E)= $\frac{number\;of\;favorable\;cases}{total\;number\;of\;cases}$

Using the formula

Then, we get

Total number of cases=4

Number of favorable cases to event A=2

$P(A)=\frac{2}{4}=\frac{1}{2}$

Number of favorable cases to event B=2

Number of favorable cases to event C=2

$P(B)=\frac{2}{4}=\frac{1}{2}$

$P(C)=\frac{2}{4}=\frac{1}{2}$

If the two events A and B are independent then

$P(A)\cdot P(B)=P(A\cap B)$

$P(A\cap)=\frac{1}{4}$

$P(B\cap C)=\frac{1}{4}$

$P(A\cap C)=\frac{1}{4}$

$P(A)\cdot P(B)=\frac{1}{2}\cdot \frac{1}{2}=\frac{1}{4}$

$P(B)\cdot P(C)=\frac{1}{4}$

$P(A)\cdot P(C)=\frac{1}{4}$

$P(A)\cdot P(B)=P(A\cap B)$

Therefore, A and B are independent

$P(B)\cdot P(C)=P(B\cap C)$

Therefore, B and C are independent

$P(A\cap C)=P(A)\cdot P(C)$

Therefore, A and C are independent.

Hence, A, B and C are pairwise independent.

6 0

3 years ago

Solve the equation.<br> -6b + 4 + 4b = -3b + 9

klemol [59]

Answer:

b=5..............is the answer

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3 years ago

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Factor x^2 + 12x + 36

larisa [96]

Answer:

(x + 6 )(x + 6 )

2 numbers to add to 12 but also multiply to get 36

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3 years ago

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