Answer:
Step-by-step explanation:
Doing this the long way, write a^12 as a product of "a"s
a^12 = a * a * a * a * a * a * a * a * a * a * a * a
Now group them into groups of 4
a^12 = a * a * a * a * a * a * a * a * a * a * a * a
There are 3 groups of 4 so you can write it as [(a^4)]^3 which is a cube
Now do the same thing with groups of 6s
a^12 = a * a * a * a * a * a * a * a * a * a * a * a
a^12 = (a^6)^2
So the two answers are
Perfect cube: [(a^4)]^3
Perfect square: (a^6)^2
Answer:
1. -2, -4
2. 7, ½
3. -2, -3
Step-by-step explanation:
1) -x² - 6x - 8 = 0
x² + 6x + 8 = 0
x² + 4x + 2x + 8 = 0
x(x + 4) + 2(x + 4) = 0
(x + 2)(x + 4) = 0
x = -2 , -4
2) 2x² - 15x + 7
2x² - 14x - x + 7 = 0
2x(x - 7) - (x - 7) = 0
(2x - 1)(x - 7) = 0
x = ½, 7
3) 3x² + 15x + 18 = 0
x² + 5x + 6 = 0
x² + 3x + 2x + 6 = 0
x(x + 3) + 2(x + 3) = 0
(x + 3)(x + 2) = 0
x = -2, -3
Answer:
B
Step-by-step explanation:
Hope this helped that's all.
Answer:
P = 4n
Step-by-step explanation:
P = n + n + n + n
If you combine all the like terms you end up with:
P = 4n
