"<span>Wilma predicts rolling a 2 about 50 times if she rolls a die 300 times" is the one situation among the following choices given in the question that shows the </span><span>appropriate use of the law of large numbers. The correct option among all the options that are given in the question is the first option or option "a". I hope it helped you.</span>
1) cf= 24 hours/1 day, 1 hour/60 minutes
30 x 1/60 = .5
10 x 24/1 = 240
240 + .5 = 240.5 hours
2) cf = 24 hours/1 day, 60 minutes/1 hour, 12 inches/1 foot
a) 0.6 x 12/1 = 7.2 inches
b) 7.2 x 1/24 = 0.3 inches per hour
Find an equation of the plane that contains the points p(5,−1,1),q(9,1,5),and r(8,−6,0)p(5,−1,1),q(9,1,5),and r(8,−6,0).
topjm [15]
Given plane passes through:
p(5,-1,1), q(9,1,5), r(8,-6,0)
We need to find a plane that is parallel to the plane through all three points, we form the vectors of any two sides of the triangle pqr:
pq=p-q=<5-9,-1-1,1-5>=<-4,-2,-4>
pr=p-r=<5-8,-1-6,1-0>=<-3,5,1>
The vector product pq x pr gives a vector perpendicular to both pq and pr. This vector is the normal vector of a plane passing through all three points
pq x pr
=
i j k
-4 -2 -4
-3 5 1
=<-2+20,12+4,-20-6>
=<18,16,-26>
Since the length of the normal vector does not change the direction, we simplify the normal vector as
N = <9,8,-13>
The required plane must pass through all three points.
We know that the normal vector is perpendicular to the plane through the three points, so we just need to make sure the plane passes through one of the three points, say q(9,1,5).
The equation of the required plane is therefore
Π : 9(x-9)+8(y-1)-13(z-5)=0
expand and simplify, we get the equation
Π : 9x+8y-13z=24
Check to see that the plane passes through all three points:
at p: 9(5)+8(-1)-13(1)=45-8-13=24
at q: 9(9)+8(1)-13(5)=81+9-65=24
at r: 9(8)+8(-6)-13(0)=72-48-0=24
So plane passes through all three points, as required.
Answer:
the Larger poster is 9ft long by 6ft wide
Step-by-step explanation:
In order to find the length and width values of the large poster we first need to find the width of the smaller poster since we are already given the length. Since we are also provided with the perimeter we can add the length twice and subtract it from the perimeter which would give us the value of both width sides of the rectangle, then we simply divide by 2 to get the value of the individual width.
10ft = 3ft + 3ft + w + w
10ft = 6ft + 2w
4ft = 2w
2ft = w
Since the larger poster is 3 times as big for the length and the width we simply multiply the smaller poster's length and width by 3...
L = 3 * 3 = 9ft
W = 2 * 3 = 6ft
Finally, we can see that the Larger poster is 9ft long by 6ft wide
Answer:
![x=30\°](https://tex.z-dn.net/?f=x%3D30%5C%C2%B0)
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
m∠LOM+m∠MON=m∠LON ----> by angle addition postulate
we have
m∠LOM=2x°
m∠MON=x°
m∠LON=90° ----> is a right angle
substitute the values
![2x+x=90](https://tex.z-dn.net/?f=2x%2Bx%3D90)
solve for x
![3x=90](https://tex.z-dn.net/?f=3x%3D90)
![x=30\°](https://tex.z-dn.net/?f=x%3D30%5C%C2%B0)