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vodka [1.7K]
3 years ago
5

I need all the angles of all four please, I uploaded them in order of each question

Mathematics
1 answer:
adelina 88 [10]3 years ago
8 0

Answer:

Blurry

Step-by-step explanation:

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Dividends Per Share Seventy-Two Inc., a developer of radiology equipment, has stock outstanding as follows: 60,000 shares of cum
Sergeeva-Olga [200]

The dividends per share on each class of stock for each of the four years for Seventy-Two Inc. are as follows:

<h3>Cumulative Preferred Stock:</h3>

                                            Year 1       Year 2        Year 3           Year 4

Distributed Dividends    $32,000    $40,000    $36,000        $36,000

Outstanding shares          60,000      60,000      60,000           60,000

Dividend per share           $0.53       $0.67          $0.60             $0.60

<h3>Common Stock:</h3>

                                          Year 1       Year 2        Year 3           Year 4

Distributed Dividends    $0              $32,000     $44,000       $64,000

Outstanding shares        400,000    400,000     400,000       400,000

Dividend per share        $0              $0.08            $0.11              $0.16

<h3>Data and Calculations:</h3>

                              3% Cumulative Preferred       Common Stock

Outstanding shares          60,000                        400,000

Par Value                            $20                              $25

Total value                       $1,200,000              $10,000,000

Annual dividend            $36,000 ($1,200,000 x 3%)

                                            Year 1       Year 2        Year 3           Year 4

Distributed Dividends    $32,000    $72,000    $80,000       $100,000

Cumulative Preferred      $32,000    $40,000    $36,000        $36,000

Common Stock                $0              $32,000    $44,000        $64,000

Learn more about dividends at brainly.com/question/25845157

#SPJ1

3 0
2 years ago
The point (17,−9) is translated to the point (6,2). Select the description of the translation.
zubka84 [21]

Answer:

11 up , 11 left

Step-by-step explanation:

Given

(17, -9) to (6,2)

Required

Determine the translation rule

Considering the x coordinates.

From 17 to 6

6 is to the left of 17.

Using the translation rule:

x = x' + b

17 = 6 + b

17 - 6 = b

11 = b

b = 11

<em>Hence: From 17 to 6 is 11 units left translation</em>

Considering the y coordinates.

From -9 to 2

2 is at the top -9.

Using the translation rule:

y = y' + b

-9 = 2 + b

-9 - 2 = b

-11= b

b = -11

The negative value impies a upward translation.

Hence: From -9 to 2 is 11 units up translation

4 0
3 years ago
Easy question.. giving brainliest<br> x/16 = 10/36<br> x=_
irina [24]

Answer:

x=40/9

Step-by-step explanation:

\frac{x}{16}  =  \frac{10}{36}  |first \: you \: cross \: multiply|  \\ x(36) = 16(10)  |open \: bracket  |  \\ 36x = 160 |divide \: both  \: side \:by \: 36 |  \\  \frac{36x}{36}  =  \frac{160}{36}  \\ x = \frac{40}{9}

6 0
3 years ago
Please help me 50 points.
kolezko [41]
First we have to convert 60 feet to inches.  since there are 12 inches in a foot we will multiply by 12
60×12=720
since the real thing is 720 inches and the scale drawing is 15 inches we can make a ratio
720:15
then simpliy
48:1
would be your answer.  It means that for every 48 inches it is in real life the scale drawing will be one inch

3 0
3 years ago
Read 2 more answers
What is the surface area of the pyramid formed from the net shown here? The triangles are equilateral, and each triangle has a h
azamat

Answer:

62.4 square centimeters

Step-by-step explanation:

The picture of the question in the attached figure

we know that

The surface area of the triangular pyramid is equal to the area of the triangular base plus the area of its three lateral triangular faces

In this problem the triangles are equilateral, that means, the

surface area is equal to the area of four congruent equilateral triangles

so

A=4[\frac{1}{2}(b)(h)]

we have

b=6\ cm\\h=5.2\ cm

substitute

A=4[\frac{1}{2}(6)(5.2)]=62.4\ cm^2

3 0
3 years ago
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