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3 years ago

I need help with a 8th grade math question, please. Will rate

Mathematics

2 answers:

larisa [96]3 years ago

3 0

Answer:

What is the question?

Step-by-step explanation:

daser333 [38]3 years ago

3 0

Okay what do you need help with

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erica [24]

Answer: 67.725feet²

Step-by-step explanation:

A heptagon consist of 7 sides and Its area is calculated using the formula

= 1/2 × nsr

n = number of sides = 7

s = side length = 4.3

r = apothem = 4.5

Area = 1/2 × nsr

= 1/2 × 7 × 4.3 × 4.5

= 0.5 × 7 × 4.3 × 4.5

= 67.725feet²

7 0

3 years ago

12 problems in45 mins 20 problems in how much time

Anni [7]

Answer:

75 mins or 1 hour 15 min :)

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

An athlete completes a race in 55.72 seconds. How many times greater is the digit in the tens place than the digit in the ones p

MArishka [77]

As they are the same the answer is 1 times

8 0

3 years ago

I don't understand this

Taya2010 [7]

The answer to the problem is B.

7 0

3 years ago

Read 2 more answers

[10] In the following given system, determine a matrix A and vector b so that the system can be represented as a matrix equation

irina1246 [14]

Answer:

$y=-\frac{158}{579}$

Step-by-step explanation:

To find the matrix A, took all the numeric coefficient of the variables, the first column is for x, the second column for y, the third column for z and the last column for w:

$A=\left[\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right]$

And the vector B is formed with the solution of each equation of the system: $b=\left[\begin{array}{c}3\\-3\\6\\1\end{array}\right]$

To apply the Cramer's rule, take the matrix A and replace the column assigned to the variable that you need to solve with the vector b, in this case, that would be the second column. This new matrix is going to be called $A_{2}$ .

$A_{2}=\left[\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right]$

The value of y using Cramer's rule is:

$y=\frac{det(A_{2}) }{det(A)}$

Find the value of the determinant of each matrix, and divide:

$y==\frac{\left|\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right|}{\left|\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right|} =\frac{158}{-579}$

$y=-\frac{158}{579}$

7 0

3 years ago