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shepuryov [24]
3 years ago
7

Solve for x ax-bx/x+c = d, if a =/b+d

Mathematics
1 answer:
erica [24]3 years ago
7 0

Answer:

dc/a-b-d

Step-by-step explanation:

ax – bx = d

x + c

Multiply both sides by x + c

ax – bx

(x + c) = d(x + c)

x + c

Simplify

ax – bx

(x+c): ax – bx

x + c

ax – bx = d(x+c)

Expand d(x+c): dx + cd

ax — bx = dx + cd

Subtract dx from both sides

ax – bx – dx = dx + cd – dx

Simplify

ax – bx – dx = cd

Factor ax – bx – dx: x(a – b – d)

x(a - b- d) = cd

Divide both sides by a – b – d; a + b + d

x(a – b - d) cd

a + b + d

a - b - d

a – b-d

Simplify

X =dc/a-b-d

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In a parallel circuit, ET = 208 V, R = 33 kΩ, and XL = 82 kΩ. What is the apparent power?
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Answer:

Apparent power is 1.413Volt-Amps.

Step-by-step explanation:

We are given that in a parallel circuit,E_{T}=208V,R=33kΩ and X_{L}=82kΩ.

And we are asked to find apparent power.

Apparent power is the combination of true power and reactive power.

In other words, we can say that in a power triangle apparent power is the hypotenuse where as true power and reactive powers are sides.

Let us find true power , reactive power first and the using Pythagorean theorem we can find apparent power.

True power=\frac{E_{T}^{2}}{R}=\frac{208^{2}}{33000}=1.311watts

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Answer:

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