Answer:
in 8 years each school will have about 1,040 students
Step-by-step explanation:
let 'x' = years
y = 30x + 800
y = -25x + 1240
30x + 800 = -25x + 1240
55x = 440
x = 8
Answer:
The correct option is (b).
Step-by-step explanation:
If X
N (µ, σ²), then
, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z
N (0, 1).
The distribution of these z-variate is known as the standard normal distribution.
The mean and standard deviation of the active minutes of students is:
<em>μ</em> = 60 minutes
<em>σ </em> = 12 minutes
Compute the <em>z</em>-score for the student being active 48 minutes as follows:
![Z=\frac{X-\mu}{\sigma}=\frac{48-60}{12}=\frac{-12}{12}=-1.0](https://tex.z-dn.net/?f=Z%3D%5Cfrac%7BX-%5Cmu%7D%7B%5Csigma%7D%3D%5Cfrac%7B48-60%7D%7B12%7D%3D%5Cfrac%7B-12%7D%7B12%7D%3D-1.0)
Thus, the <em>z</em>-score for the student being active 48 minutes is -1.0.
The correct option is (b).
Answer:
We conclude that there is no change in the average weight since the implementation of a new breakfast and lunch program at the school.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 100 pounds
Sample mean,
= 98 pounds
Sample size, n = 35
Alpha, α = 0.05
Population standard deviation, σ = 7.5 pounds
First, we design the null and the alternate hypothesis
We use one-tailed(left) z test to perform this hypothesis.
Formula:
Putting all the values, we have
Now,
We calculate the p-value with the help of standard normal table.
P-value = 0.057398
Since the p-value is greater than the significance level, we fail to reject the null hypothesis and accept is.
We conclude that there is no change in the average weight since the implementation of a new breakfast and lunch program at the school.
Answer:
f(-3)= 5
Step-by-step explanation:
f(x) = 2x+1 f(-3) -3 is the input.
= 2(-3)+1
= -6+1
f(-3) = -5
Hope this helps :)
Answer:
45cm^2
Step-by-step explanation:
split the shape into a triangle and rectangle between points FE. Count how many squares up on the rectangle = 2cm
squares across = 9cm
2cm x 9cm = 18cm^2
for the triangle across would be 9cm
hight would be 6cm
9cm x 6cm = 54cm/2 = 27cm^2
18cm^2 + 27cm^2 = 45cm^2