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3 years ago

9

Can anyone help me determine the next terms in these sequences?

1 answer:

Ipatiy [6.2K]3 years ago

7 0

Answer:

132235

Step-by-step explanation:

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Evaluate: 32 + (8 − 2) • 4 − 6/3

Ipatiy [6.2K]

The expression to evaluate is 32 + (8 - 2) * 4 - 6/3. In the first step you can solve the parenthesis and the fraction => 32 + (6)*4 - 2. In the second step you mutiply 6*4 => 32 + 24 - 2. Finally, you do the maths: 32 + 24 - 2 = 54. <span>Answer: 54</span>

8 0

3 years ago

I need help pls WILL GIVE BRAINLIEST

Alex73 [517]

Answer: (3,-2)

Step-by-step explanation:

$-3x-7y=5\\15x+6y=33$

$5(-3x-7y)=5(5)\\-15x-35y=25$

new system:

$-15x-35y=25\\15x+6y=33$

add.

$-29y=58\\y=-2$

plug in -2 for y

$-3x-7(-2)=5\\-3x+14=5\\-3x=-9\\x=3$

system:

$(3,-2)$

4 0

2 years ago

Read 2 more answers

Consider this quadratic equation. x^2+2x+7=21 The number of positive solutions to this equation is ____. The approximate value o

babunello [35]

Answer:

Step-by-step explanation:

7 0

3 years ago

You measure 20 turtles' weights, and find they have a mean weight of 45 ounces. Assume the population standard deviation is 11.5

Naily [24]

Answer: the maximal margin of error associated with a 90% confidence interval for the true population mean turtle weight = 4.23

Step-by-step explanation:

Formula for margin of error : $E=\dfrac{z^*\times (Population\ standard\ deviation)}{\sqrt{Sample\ size}}$

, where z* = Critical z-value.

Given: population standard deviation = 11.5 ounces

Sample size = 20

Z value for 90% confidence level = 1.645

margin of error (E) = $\dfrac{1.645\times11.5}{\sqrt{20}}$

$\approx4.23$

Hence, the maximal margin of error associated with a 90% confidence interval for the true population mean turtle weight = 4.23

3 0

3 years ago

PLEASE PLEASE HELP!!!

nignag [31]

Answer:

Step-by-step explanation:

$x^{2} \sqrt{x} \sqrt[n]{x} \frac{x}{y} x_{123} \beta \beta \alpha \neq \geq \\ \left \{ {{y=2} \atop {x=2}} \right.$

3 0

3 years ago