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postnew [5]
3 years ago
15

Name the SMALLEST subset to which each value belongs:

Mathematics
2 answers:
rjkz [21]3 years ago
8 0

Answer:

Hi how are you doing today Jasmine

Oliga [24]3 years ago
7 0

Answer:

A.

Step-by-step explanation:

Natural- 123.......

Whole- 01234......

Irrational- -2-1-30123

Rationals- decimals and fractions plus all Irrationial numbers

7 and -2 both are Irrational and Rational but Irrational is smaller!!!

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Find the slope on the graph
alukav5142 [94]

Answer:

3/1

Step-by-step explanation:

you need to count the hight of the line from the (0,2) which will be 3 and then how much of the distance of x is. I used rise over run.

6 0
3 years ago
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If x^2+1/x^2=3 find the value of x^2/(x^2+1)^2<br> Express answer as a common fraction.<br> Thanks!!
timama [110]

x^2+\dfrac1{x^2}=3\implies x^4+1=3x^2\implies x^4-3x^2+1=0

By the quadratic formula,

x^2=\dfrac{3\pm\sqrt5}2\implies x^2+1=\dfrac{5\pm\sqrt5}2

Then

(x^2+1)^2=\dfrac{25\pm10\sqrt5+5}4=\dfrac{15\pm5\sqrt5}2

\implies\dfrac{x^2}{(x^2+1)^2}=\dfrac{\frac{3\pm\sqrt5}2}{\frac{15\pm5\sqrt5}2}=\dfrac{3\pm\sqrt5}{15\pm5\sqrt5}

Multiply numerator and denominator by the denominator's conjugate:

\dfrac{3\pm\sqrt5}{15\pm5\sqrt5}\cdot\dfrac{15\mp5\sqrt5}{15\mp5\sqrt5}=\dfrac{45\pm15\sqrt5\mp15\sqrt5-25}{15^2-(5\sqrt5)^2}=\dfrac{20}{100}=\dfrac15

3 0
3 years ago
Part A Mr. Bade spends an average of $42.50 during a five-day workweek on lunch.if he eats every day during his 5-day workweek,
trasher [3.6K]

Answer:

Part A: He spends an average of $8.50 per day

Part B:  He would save $17 per week

Step-by-step explanation:

4 0
3 years ago
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The perimeter of the rectangle is 22 meters, and the perimeter of the triangle is 12 meters. Find the dimensions of the rectangl
lianna [129]

Answer:

Length:8 m

Width:3 m

Step-by-step explanation:

<u><em>The complete question is</em></u>

If the perimeter of a rectangle is 22 meters, and the perimeter of a right triangle is 12 meters (the sides of the triangle are half the length of the rectangle, the width of the rectangle, and the hypotenuse is 5 meters). How do you solve for L and W, the dimensions of the rectangle.

step 1

<em>Perimeter of rectangle</em>

we know that

The perimeter of rectangle is equal to

P=2(L+W)

we have

P=22\ m

so

22=2(L+W)

Simplify

11=L+W -----> equation A

step 2

Perimeter of triangle

The perimeter of triangle is equal to

P=\frac{L}{2}+W+5

P=12\ m

so

12=\frac{L}{2}+W+5

Multiply by 2 both sides

24=L+2W+10

L+2W=14 ----> equation B

Solve the system of equations by graphing

Remember that the solution is the intersection point both graphs

using a graphing tool

The solution is the point (8,3)

see the attached figure

therefore

The dimensions of the rectangle are

Length:8 m

Width:3 m

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3 years ago
Simonne, Marco, and Evon were partners in
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Evon got $450 .........
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