The coefficient of (3y² + 9)5 is <u>15</u>.
A polynomial is of the form a₀xⁿ + a₁xⁿ⁻¹ + a₂xⁿ⁻² + ... + aₙ₋₁x + aₙ.
Here, x is the variable, aₙ is the constant term, and a₀, a₁, a₂, ..., and aₙ₋₁, are the coefficients.
a₀ is the leading coefficient.
In the question, we are asked to identify the coefficient of (3y² + 9)5.
First, we expand the given expression:
(3y² + 9)5
= 15y² + 45.
Comparing this to the standard form of a polynomial, a₀xⁿ + a₁xⁿ⁻¹ + a₂xⁿ⁻² + ... + aₙ₋₁x + aₙ, we can say that y is the variable, 15 is the coefficient, and 45 is the constant term.
Thus, the coefficient of (3y² + 9)5 is <u>15</u>.
Learn more about the coefficients of a polynomial at
brainly.com/question/9071229
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Hey there! :D
Slope intercept form: y=mx+b
4x-2y=9
Add 2y to the other side.
4x=9+2y
Subtract 9 on both sides.
4x-9=2y
Flip the equation over.
2y=4x-9 <== slope intercept form
I hope this helps!
~kaikers
Answer:11.7
Step-by-step explanation:
Answer:
21x + 12
Step-by-step explanation:
correct me of i am wrong
Answer:
September 18 is the due date
Step-by-step explanation:
the rest of March = 19 days
April has 30
may has 31
june has 30
july has 31
and August has 31 also
...if we add all of those days it equals to 172 days....u need approximately 18 more days to make the 190 days (due date) ;take 18 days out of September ....making the due date the 18th of September
