Answer:
ok
Step-by-step explanation:
thenekljqwklfmk,f zd,?c /z
317÷8= <span>39.625 so then round it down and you get 39. So 39 marbles in each bowl
hope this helps :-)
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Answer:
a) Binomial.
b) n=20, p=0.01, k≥2
The probability hat a package sold will be refunded is P=0.0169.
Step-by-step explanation:
a) We know that
- the defective probability is constant and independent.
- the sample size is bigger than one subject.
The most appropiate distribution to represent this random variable is the binomial.
b) The parameters are:
- Sample size (amount of clips in the package): n=20
- Probability of defective clips: p=0.01.
- number of defective clips that trigger the money-back guarantee: k≥2
The probability of the package being refunded can be calculated as:
![P(x\geq2)=1-(P(x=0)+P(x=1))\\\\\\P(x=k) = \dbinom{n}{k} p^{k}q^{n-k}\\\\\\P(x=0) = \dbinom{20}{0} p^{0}q^{20}=1*1*0.8179=0.8179\\\\\\P(x=1) = \dbinom{20}{1} p^{1}q^{19}=20*0.01*0.8262=0.1652\\\\\\P(x\geq2)=1-(0.8179+0.1652)=1-0.9831=0.0169](https://tex.z-dn.net/?f=P%28x%5Cgeq2%29%3D1-%28P%28x%3D0%29%2BP%28x%3D1%29%29%5C%5C%5C%5C%5C%5CP%28x%3Dk%29%20%3D%20%5Cdbinom%7Bn%7D%7Bk%7D%20p%5E%7Bk%7Dq%5E%7Bn-k%7D%5C%5C%5C%5C%5C%5CP%28x%3D0%29%20%3D%20%5Cdbinom%7B20%7D%7B0%7D%20p%5E%7B0%7Dq%5E%7B20%7D%3D1%2A1%2A0.8179%3D0.8179%5C%5C%5C%5C%5C%5CP%28x%3D1%29%20%3D%20%5Cdbinom%7B20%7D%7B1%7D%20p%5E%7B1%7Dq%5E%7B19%7D%3D20%2A0.01%2A0.8262%3D0.1652%5C%5C%5C%5C%5C%5CP%28x%5Cgeq2%29%3D1-%280.8179%2B0.1652%29%3D1-0.9831%3D0.0169)
Answer:
√7x−49√x
Explanation:
First of all, expand by multiplying √7x⋅√x and √7x⋅7√7respectively:
√7x(√x−7√7)=√7x⋅√x−√7x⋅7√7
... you can express √7x as √7⋅√x...
=√7⋅√x⋅√x−√7⋅√x⋅7⋅√7
=√7⋅(√x)2−(√7)2⋅√x⋅7
... the operations squaring and taking the square root "eliminate each other"...
=√7⋅x−7⋅√x⋅7
=√7x−49√x
Hope that this helped!