A) Here, sum of two non-adjacent angles: 52 + 25 = 77
Now, ∠3 = 180 - 77 [ sum of all angles in a triangle is 180 ]
so, ∠3 = 103
Now, ∠3 + ∠4 = 180 [ Supplementary angles ]
So, ∠4 = 180 - ∠3
∠4 = 180 - 103 = 77
∠4 = 77 [ which is sum of two non-adjacent angles ]
....Hence proved.
b) m∠4 = 77
[ Solved in previous section ]
Hope this helps!
It has to do with the unit circle, I think it is A because it should be 2(0+ (-1)) but I would probably wait for someone to come behind me and explain it better sorry couldn't help more
Answer:
Step-by-step explanation:
1) ?
I can't see what that one given angle is .. but it's that mystery angle subtracted from 180 give the angle BOA then you know that's an isosceles triangle again that the BOA is part of... so then just subtract BOA from 180 to find the two other angle of that triangle... they are the small so just divide your answer of 180-BOA /2 is the angle of each.. then since you know those to smaller angles subtract one from 90 to find the angle BAX
2) ( as we would read normally)
You're making this really tough on me.. I can just barely read the equations
I think it's 1+6x and 7x-3 . b/c they are the same length sides you can set those equal
1+6x = 7x -3
4+6x = 7x
4 = x
that worked out well :
for the tangent.. it's Tan(Ф)= Opp/ Adj
but I don't know which side they want to solve for.. I think you may have left off some of the instructions???? :/
ohh I think they really mean.. what's the length of the tangent lines .. that was confusing to me.. :/ just plug in 4 into x for either eq.
1+6(4) = 25
or
7(4)-3=25
tangent is 25
3)
x-2 = 2x-10
x+8 = 2x
8 = x
again they made it work out easy :)
Then plug 8 into either equation to find the length of the tangent lines
8-2=10
tangent is 10
4) = 2) ??? they are the same question maybe you meant to put something else?
Answer:
h³- 8h² + 16h
Step-by-step explanation:
The problem tells us that the length and width of these boxes are both 4 inches less than the height of the box.
So if we name <u>h the height of the box</u>, the <u>width of the box would be h - 4 </u>and the <u>height of the box would be h - 4.</u>
Now, the volume of a rectangular prism is given by V = height x width x length
So, considering the values we have in this problem we get:
V= height x width x volume
V = h (h-4)(h-4)
V= h(h-4)²
V= h (h²-8h + 16)
V = h³- 8h² + 16h
Therefore, the polynomial representing the volume of this box in terms of the height is h³- 8h² + 16h
