1. The range of a function is the set of all values that f can produce for all the x-es in the domain.
2. If we are given the graph, in order to find the range, we project the graph into the y axis. Informally, we draw the "shadow" of the graph into the y axis as in the FIGURE atached.
3. The range is <span>D || {y | −5 ≤ y ≤ −1}</span>
Answer:
64.01
Step-by-step explanation:
tan∅= p/b
tan58= x/40
or, x= 40×tan58
x = 64.01
Answer:
m=3/4
Step-by-step explanation:
first, let's put the line 4x+3y=9 from standard form (ax+by=c) into slope-intercept form (y=mx+b)
we have the equation 4x+3y=9
subtract 4x from both sides
3y=-4x+9
divide by 3
y=-4/3x+3
perpendicular lines have slopes that are negative and reciprocal. If the slopes are multiplied together, the result is -1
so to find the slope of the line perpendicular to the line y=-4/3x+3, we can take the slope of y=-4/3x+3 (-4/3) multiply it by a variable (this is our unknown value), and have that set to -1
(m is the slope value)
-4/3m=-1
multiply by -3/4
m=3/4
therefore the slope of the perpendicular line is 3/4
hope this helps!! :)
I don’t think she likes you but she is ok I will try and see her this weekend I don’t want you have wrt
6x - 9x - 5 =
combine like terms
6 - 9 = - 3
- 3x - 5 =
leave x by itself
- 3x - 5 =
+3x
___
0
- 5 = 3x
solve for x (division)
- 5 = 3x
___
3
-5/3 = x OR x = -5/3
