Answer: the probability that fewer than 100 in a random sample of 818 men are bald is 0.9830
Step-by-step explanation:
Given that;
p = 10% = 0.1
so let q = 1 - p = 1 - 0.1 = 0.9
n = 818
μ = np = 818 × 0.1 = 81.8
α = √(npq) = √( 818 × 0.1 × 0.9 ) = √73.62 = 8.58
Now to find P( x < 100)
we say;
Z = (X-μ / α) = ((100-81.8) / 8.58) = 18.2 / 8.58 = 2.12
P(x<100) = P(z < 2.12)
from z-score table
P(z < 2.12) = 0.9830
Therefore the probability that fewer than 100 in a random sample of 818 men are bald is 0.9830
Answer: 18,000
Step-by-step explanation: 10,000 borrowed + the 4% earned x the amount paid within 20 years
Total number of bulbs = 64
Number of defective bulbs = 10
Number of good bulbs = 64 - 10 = 54
P(5 good bulbs) = (54/64)⁵ = (27/32)⁵ = 0.428
Answer: 0.428
What you can use for this case is a function of the potential type.
We have then
y = a (b) ^ x
Where we have:
Walker starts the fund by depositing $ 5
a = 5
Each week the balance of the fund is twice the balance of the previous week:
b = 2
The function is:
y = 5 (2) ^ x
The number of weeks to reach $ 1280 is 8 weeks.
Check:
y = 5 (2) ^ 8
y = 1280
Answer:
An equation can be used to find the number of weeks, x, after which the balance of the fund will reach $ 1,280 is:
y = 5 (2) ^ x
The number of weeks that it takes to reach the class goal is
8 weeks
Answer:
0.762 = 76.2% probability that this shipment is accepted
Step-by-step explanation:
For each pen, there are only two possible outcomes. Either it is defective, or it is not. The probability of a pen being defective is independent from other pens. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which 
is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
17 randomly selected pens
This means that 
(a) Find the probability that this shipment is accepted if 10% of the total shipment is defective. (Use 3 decimal places.)
This is 
when 
. So
0.762 = 76.2% probability that this shipment is accepted
