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Naddik [55]
3 years ago
7

2m^2-5m-3=0 by factorization​

Mathematics
1 answer:
slamgirl [31]3 years ago
6 0

Answer:

M= 6, -1

Step-by-step explanation:

Factoring these numbers, it will result in (m-6)(m+1). So, m= 6,-1

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Calculate the length of AC to one decimal place in the trapezium below.
a_sh-v [17]

Answer:

First we will split trapezium on two geometric figure.

One is rectangle and the second is right triangle.

When we subtract 11-4=7cm  we get one cathetus of the right triangle a=7cm also we know hypotenuse which is c=16cm.

We will use Pythagorean theorem to find the second cathetus b

b=√16∧2-7∧2= √256-49= √207 ≈ 14.39cm =DC =>

AC =√(DC)∧2+(AD)∧2= √14.39∧2+11∧2= √207+121= √328= 18.1cm

AC=18.1cm

Good luck!!

7 0
3 years ago
What is the solution of the equation over the complex numbers
denis-greek [22]

<u>Answer:</u>

2i\sqrt{3}

-2i\sqrt{3}

<u>Step-by-step explanation:</u>

x^2 + 12

First set the equation to 0

x^2 + 12

x^2 + 12 = 0

Second, get the 12 on the right side of the equal sign by adding a -12 to each side

x^2 + 12 = 0

x^2 + 12 + (-12) = 0 -12

x^2 = -12

Square root both sides of the equal sign.

x^2 = -12

\sqrt{x^2} = \sqrt{-12}

Take the square root on left sides of the equal sign.

\sqrt{x^2} = \sqrt{-12}

x = \sqrt{-12}

Take the square root on the right side of the equal sign. Remember \sqrt{-1} = i

x = \sqrt{-12}

x = \sqrt{4}*\sqrt{-1}\sqrt{3}}

x = 2i\sqrt{3}

<u>AND</u>

x = -2i\sqrt{3}

8 0
3 years ago
You have a nickle and a number cube with numbers 1 - 6. How many possible outcomes would there be?
Vadim26 [7]

I believe that is 12

Very sorry if I am wrong

6 0
3 years ago
Hey I’m confused on this problem help.
PilotLPTM [1.2K]

the answer is b carmella

7 0
3 years ago
Triangle FGH with vertices F(6,6), G(8,8), and H(8,3): (a) Reflection: in the line x = 5 (b) Translation: (x,y)→ (x - 7, y - 9)
irakobra [83]

(a) The vertices after the reflection in the line x = 5 are F'(4,6) , G'(2,8) , H'(2,3) .

and (b) after translation , the vertices are F''(-1,-3) , G'' (1,-1) , H''(1,-6) .

In the question a triangle FGH with vertices F(6,6) , G(8,8) and H(8,3) is given

Part (a)

the rule for reflection of point (x,y) by the line x = p  is

(x,y) → (2×p - x , y)

reflection by the line x = 5 ,

we get

the vertices as

F'(2×5-6,6) = (4,6)

G'(2×5-8,8) = (2,8)

H'(2×5 - 8 ,3) = (2,3)

Part (b)

the rule of translation is given as (x,y)→ (x - 7, y - 9)

So , the vertices after translation are

F''(6-7 , 6-9) = (-1,-3)

G''(8-7,8-9) = (1,-1)

H''(8-7,3-9) = (1,-6)

Therefore , (a) The vertices after the reflection in the line x = 5 are F'(4,6)

G'(2,8) , H'(2,3) .

and (b) after translation , the vertices are F''(-1,-3) , G'' (1,-1) , H''(1,-6) .

Learn more about Translation here

brainly.com/question/3456459

#SPJ1

7 0
1 year ago
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