2m^2-5m-3=0 by factorization
1 answer:
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<u>Answer:</u>
<u>Step-by-step explanation:</u>
First set the equation to 0
Second, get the 12 on the right side of the equal sign by adding a -12 to each side
Square root both sides of the equal sign.
Take the square root on left sides of the equal sign.
Take the square root on the right side of the equal sign. Remember
<u>AND</u>
(a) The vertices after the reflection in the line x = 5 are F'(4,6) , G'(2,8) , H'(2,3) .
and (b) after translation , the vertices are F''(-1,-3) , G'' (1,-1) , H''(1,-6) .
In the question a triangle FGH with vertices F(6,6) , G(8,8) and H(8,3) is given
Part (a)
the rule for reflection of point (x,y) by the line x = p is
(x,y) → (2×p - x , y)
reflection by the line x = 5 ,
we get
the vertices as
(2×5-6,6) = (4,6)
G'(2×5-8,8) = (2,8)
H'(2×5 - 8 ,3) = (2,3)
Part (b)
the rule of translation is given as (x,y)→ (x - 7, y - 9)
So , the vertices after translation are
F''(6-7 , 6-9) = (-1,-3)
G''(8-7,8-9) = (1,-1)
H''(8-7,3-9) = (1,-6)
Therefore , (a) The vertices after the reflection in the line x = 5 are F'(4,6)
G'(2,8) , H'(2,3) .
and (b) after translation , the vertices are F''(-1,-3) , G'' (1,-1) , H''(1,-6) .
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