Find the equation of a straight line that has a gradient of 4 and passes through the point (1,10)
2 answers:
Answer:
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Step-by-step explanation:
Point, slope form: [y-y1=m(x-x1)]
y-4=2(x-1)
Distribute:
y-4=2x-2
Add 4 on both sides
y=2x+2
There's your answer.
Answer: Given the peculiar interrogate, the ameliorated retort to such is identified as ‘y = 4x + 6’.
Step-by-Step Explanation:
The following configurations are identified as,
Gradient: 4 units.
Point, situated in the Cartesian plane: (1, 10).
Utilizing the ‘Point-Slope Equation’:
Y- y1 = m(x - x1)
Y - 10 = 4(x - 1)
Y = 4x + 6
Henceforth, the linear structure obtains a linear configuration of ‘y = 4x + 6’.
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