Do anyone know what questions will be asked in the second DBA of geometry in flvs pls I need to know or I will ded

If you could please help, what is the missing answer? Thank you to anyone who helps out!

ICE Princess25 [194]

Answer:

48

Step-by-step explanation:

let s be the snowman, g be the girl, and t be the christmas tree

2s+g=24

2t+2ts=132

3t+2g=26

subtract 2 times the first equation from the third one to get

3t-4s=-22

from the second equation we can deduce

2t(1+s)=132

t(1+s)=66

t=66/(1+s)

Substitute:

3(66)/(1+s)-4s=-22

3(66)/(1+s)=4s-22

3(66)=(4s-22)(1+s)

3(66)=-18s+4s^2-22

4s^2-18s-220=0

using the quadratic formula, we get s = 10, s = -5.5.

2(10)+g=24

g=4

2t(1+10)=132

2t=12

t=6

So 2s+t*g= 20+6*4=48

you would get a different solution for the negative s, but since snowmen cannot be negative, 48 is the answe.r

8 0

2 years ago

Please help me. This is real confusing.

katrin2010 [14]

Answer:

1st problem: b) $A=2500(1.01)^{12t}$

2nd problem: c) $A=2500e^{.12t}$

Step-by-step explanation:

1st problem:

The formula/equation you want to use is:

$A=P(1+\frac{r}{n})^{nt}$

where

t=number of years

A=amount he will owe in t years

P=principal (initial amount)

r=rate

n=number of times the interest is compounded per year t.

We are given:

P=2500

r=12%=.12

n=12 (since there are 12 months in a year and the interest is being compounded per month)

$A=2500(1+\frac{.12}{12})^{12t}$

Time to clean up the inside of the ( ).

$A=2500(1+.01)^{12t}$

$A=2500(1.01)^{12t}$

----------------------------------------------------

2nd Problem:

Compounded continuously problems use base as e.

$A=Pe^{rt}$

P is still the principal

r is still the rate

t is still the number of years

A is still the amount.

You are given:

P=2500

r=12%=.12

Let's plug that information in:

$A=2500e^{.12t}$ .

6 0

2 years ago

Which pair of angles are corresponding?

marta [7]

Answer:

M/_! and M/_3

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Let e f (x) = x2 – 2x - 4 What is the average rate of change for the quadratic function from X = -1 tox to x = 42 Enter your ans

sammy [17]

Answer:

The average rate of change of the given function

A(x) = 1

Step-by-step explanation:

Step(i):-

Given function f(x) = x² - 2x -4

And given that x = a = -1 and x=b = 4

The average rate of change of the given function

$A(x) = \frac{f(b)-f(a)}{b-a}$

Step(ii):-

f(x) = x² - 2x -4

f(-1) = (-1)² - 2(-1) -4 = 1+2-4 = -1

f(4) = 4² -2(4) -4 = 16 -12 = 4

The average rate of change of the given function

$A(x) = \frac{f(b)-f(a)}{b-a}$

$A(x) = \frac{4-(-1)}{4-(-1)} = \frac{5}{5} = 1$

final answer:-

The average rate of change of the given function

A(x) = 1

5 0

3 years ago

Read 2 more answers

Someone who is good with algebra i equations and inequalities?

guajiro [1.7K]

Somebody? I think you can find someone like that in your school... nice profile picture.

5 0

3 years ago