1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Brut [27]
3 years ago
9

Find the value of x. If necessary, round your answer to the nearest tenth. The

Mathematics
2 answers:
Aneli [31]3 years ago
5 0

Answer:

18.8 you are right

Step-by-step explanation:

Anika [276]3 years ago
5 0

Answer:

12

Step-by-step explanation:

If two chords intersect in a circle, then (product of segments of Chord 1) = (product of segments of Chord 2)

=> 8 × 15 = 10 × x

=> x = 8 × 15 ÷ 10

=> x = 12

You might be interested in
An angle bisector of a triangle divides the opposite side of the triangle into segments 6 cm and 4 cm long. A second side of the
Usimov [2.4K]
It will probably be A Hopes This Helps.
5 0
3 years ago
I need help on this question
gladu [14]

i think A is the answer and why cant you just click the little ask for help button?

8 0
4 years ago
Read 2 more answers
Rachel saved money to buy art supplies. She used 13 of her savings to buy brushes. She used 35 of her savings to buy paint. What
vekshin1

Given:

Rachel used \dfrac{1}{3} of her savings to buy brushes.

She used \dfrac{3}{5} of her savings to buy paint.

To find:

The fraction for remaining savings.

Solution:

Fraction that Rachel used of her savings to buy brushes and paint is

\text{Fraction for used amount}=\dfrac{1}{3}+\dfrac{3}{5}

                                    =\dfrac{5+9}{15}

                                    =\dfrac{14}{15}

Now,

\text{Fraction for remaining savings}=1-\text{Fraction for used amount}

\text{Fraction for remaining savings}=1-\dfrac{14}{15}

\text{Fraction for remaining savings}=\dfrac{1}{15}

Therefore, \dfrac{1}{15} of her savings is remaining.

6 0
3 years ago
Segment AB is a ____
Butoxors [25]
The segment is referred to as a diameter
3 0
3 years ago
Read 2 more answers
EXAMPLE 5 Find the maximum value of the function f(x, y, z) = x + 2y + 11z on the curve of intersection of the plane x − y + z =
Taya2010 [7]

Answer:

\displaystyle x= -\frac{10}{\sqrt{269}}\\\\\displaystyle y= \frac{13}{\sqrt{269}}\\\\\displaystyle z = \frac{23\sqrt{269}+269}{269}

<em>Maximum value of f=2.41</em>

Step-by-step explanation:

<u>Lagrange Multipliers</u>

It's a method to optimize (maximize or minimize) functions of more than one variable subject to equality restrictions.

Given a function of three variables f(x,y,z) and a restriction in the form of an equality g(x,y,z)=0, then we are interested in finding the values of x,y,z where both gradients are parallel, i.e.

\bigtriangledown  f=\lambda \bigtriangledown  g

for some scalar \lambda called the Lagrange multiplier.

For more than one restriction, say g(x,y,z)=0 and h(x,y,z)=0, the Lagrange condition is

\bigtriangledown  f=\lambda \bigtriangledown  g+\mu \bigtriangledown  h

The gradient of f is

\bigtriangledown  f=

Considering each variable as independent we have three equations right from the Lagrange condition, plus one for each restriction, to form a 5x5 system of equations in x,y,z,\lambda,\mu.

We have

f(x, y, z) = x + 2y + 11z\\g(x, y, z) = x - y + z -1=0\\h(x, y, z) = x^2 + y^2 -1= 0

Let's compute the partial derivatives

f_x=1\ ,f_y=2\ ,f_z=11\ \\g_x=1\ ,g_y=-1\ ,g_z=1\\h_x=2x\ ,h_y=2y\ ,h_z=0

The Lagrange condition leads to

1=\lambda (1)+\mu (2x)\\2=\lambda (-1)+\mu (2y)\\11=\lambda (1)+\mu (0)

Operating and simplifying

1=\lambda+2x\mu\\2=-\lambda +2y\mu \\\lambda=11

Replacing the value of \lambda in the two first equations, we get

1=11+2x\mu\\2=-11 +2y\mu

From the first equation

\displaystyle 2\mu=\frac{-10}{x}

Replacing into the second

\displaystyle 13=y\frac{-10}{x}

Or, equivalently

13x=-10y

Squaring

169x^2=100y^2

To solve, we use the restriction h

x^2 + y^2 = 1

Multiplying by 100

100x^2 + 100y^2 = 100

Replacing the above condition

100x^2 + 169x^2 = 100

Solving for x

\displaystyle x=\pm \frac{10}{\sqrt{269}}

We compute the values of y by solving

13x=-10y

\displaystyle y=-\frac{13x}{10}

For

\displaystyle x= \frac{10}{\sqrt{269}}

\displaystyle y= -\frac{13}{\sqrt{269}}

And for

\displaystyle x= -\frac{10}{\sqrt{269}}

\displaystyle y= \frac{13}{\sqrt{269}}

Finally, we get z using the other restriction

x - y + z = 1

Or:

z = 1-x+y

The first solution yields to

\displaystyle z = 1-\frac{10}{\sqrt{269}}-\frac{13}{\sqrt{269}}

\displaystyle z = \frac{-23\sqrt{269}+269}{269}

And the second solution gives us

\displaystyle z = 1+\frac{10}{\sqrt{269}}+\frac{13}{\sqrt{269}}

\displaystyle z = \frac{23\sqrt{269}+269}{269}

Complete first solution:

\displaystyle x= \frac{10}{\sqrt{269}}\\\\\displaystyle y= -\frac{13}{\sqrt{269}}\\\\\displaystyle z = \frac{-23\sqrt{269}+269}{269}

Replacing into f, we get

f(x,y,z)=-0.4

Complete second solution:

\displaystyle x= -\frac{10}{\sqrt{269}}\\\\\displaystyle y= \frac{13}{\sqrt{269}}\\\\\displaystyle z = \frac{23\sqrt{269}+269}{269}

Replacing into f, we get

f(x,y,z)=2.4

The second solution maximizes f to 2.4

5 0
3 years ago
Other questions:
  • Need Help Asap offering 10 Points!!!!
    9·1 answer
  • Write the equation of a line passing through (5,2) parallel to y=4x-3
    7·1 answer
  • -3/10b=2/5 what is b in this equation
    6·2 answers
  • Tom has 8 toys each toy weighs either 20 grams or 40 grams or 50 grams he has a diffrent number of toys (at least one) of each w
    10·2 answers
  • Which expressions are equivalent to 7 (negative three-fourths x minus 3)? Select two options. Negative 5 and one-fourth x minus
    12·2 answers
  • What is the distance between -10 and 10 on the number line?
    12·2 answers
  • Use the information to complete the task.
    13·1 answer
  • what is an equation in slope-intercept form of the line that passes through (6,10) and is parallel to the graph of y=1/3x-1 ?
    7·1 answer
  • I really need help with this pleaseeee
    13·1 answer
  • The daily supply of oxygen for a particular multicellular organism is provided by 625 square feet of lawn. a total of 8,750 squa
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!