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Ilya [14]
2 years ago
7

The height of a triangle is 4 m more than twice the length of the base. The area of the triangle is 35 m^2 . Find the height of

the triangle
Mathematics
1 answer:
disa [49]2 years ago
6 0

Answer:

Step-by-step explanation:

Let the Base of the  △  be  x

Then the Height will be  2 x + 4

Area of △ = 1 2 b h

Where, b = b a s e , h = h e i g h t , A r e a = 35

(in this case)

Substitute the values into the equation → 35 = 1 2 ( 2 x + 4 ) ( x ) → 35 = ( 2 x + 4 ) 2 ( x ) →

35 = ( x + 2 ) ( x ) → 35 = x 2 + 2 x

Subtract  35  both sides

→ 0 = x ^2 + 2 x − 35

Rewrite the equation in the Standard form

x ^2 + 2 x − 35 = 0

Factor the equation

→ ( x + 7 ) ( x − 5 ) = 0

So we have  

x = − 7 , 5

numbers So  x = 5

They have asked us to find the Height

So, ⇒ H e i g h t = 2 x + 4 = 2

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Which ordered pair is a solution to the equation? y=x3/4
Leni [432]

Answer:

(8,6)

Step-by-step explanation:

y=x3/4

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3 years ago
Read 2 more answers
Which inequality is represented by the graph? y≥35x−1.5 y≤35x−1.5 y<35x−1.5 y>35x−1.5
Setler79 [48]

Answer:

y > 0.6x - 1.5

Step-by-step Explanation:

We need two points, to get to the equation of the graph.

Since we've got the following equation for two points (x1, y1), (x2, y2):-

\boxed{ \mathsf{ \red{y - y_{1} =  \frac{y_{2} - y_{1}}{x_{2} - x_{1}} (x - x_{1})  }}}

okay soo

I found two points that lie on this graph, not on the shaded region but yeah the dotted line which defines the graph.

one point is <u>(0, -1.5)</u> which lies on the y axis(the point where the dotted line touches the y axis)

other point is <u>(2.5, 0)</u> and this lies on the x axis

placing these points in the place of (x1, y1) and (x2, y2) in the above mentioned equation

\mathsf{\implies y - ( - 1.5) =  \frac{0 -( - 1.5)}{2.5 -0 } (x -0 )}

you can take any one as (x1, y1) or (x2, y2).

so upon solving the above equation we get

\mathsf{\implies (y  +  1.5) =  \frac{0  +  1.5}{2.5  } (x  )}

\mathsf{\implies y  +  1.5 =  \frac{ 1.5}{2.5  } x  }

\mathsf{\implies y  +  1.5 =  \frac{ \cancel{1.5}\:\:{}^3}{\cancel{2.5}\:\:{}^5 } x  }

\mathsf{\implies y  +  1.5 =  \frac{ 3}{5 } x  }

multiplying both sides by 5

\mathsf{5y + 7.5 = 3x}

okay so this is the required equation of the dotted line

now we'll find the inequality

for this check whether the origin (0,0) lies under the shaded region or not

in this case it does

so

replacing x and y with 0

\mathsf{\implies5(0) + 7.5 = 3(0)}

\mathsf{\implies0 + 7.5 = 0}

this is absurd, 7.5 is not equal to 0 so we're gonna replace that equals sign with that of inequality

7.5 is greater than 0! so,

\mathsf{\implies7.5 > 0}

this goes for the whole equation, since we didnt swap any thing from left to right side of the equation or vice versa we can use this sign, to obtain the required inequality

\mathsf{5y + 7.5 > 3x}

dividing this inequality by 5, since there's no co-efficient in front of y in the given answers

we get

y + 1.5 > 0.6x

taking 1.5 to the RHS

<h3>y > 0.6x - 1.5 </h3>

that is the last option

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