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GuDViN [60]
3 years ago
11

What is the weight shown by the arrow? (in grams please)

Mathematics
2 answers:
pickupchik [31]3 years ago
6 0
Three hundred and seventy five grams
marshall27 [118]3 years ago
3 0

Answer:

375 grams

Step-by-step explanation:

¯\_ʘ‿ʘ_/¯.......

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A linear function g models a relationship in which the dependent variable decreases 3 units for every 5 units the independent va
Sever21 [200]

Answer:

Slope=-2/3,  y-intercept=2, x-intercept=3

Step-by-step explanation:

Let the independent variable be x and dependent variable be y

y=h(x)

h is a linear function so it is represented in the general form of y=mx+c where

m is slope and c is the y-intercept.

Given "the dependent variable decreases 2 units for every 3 units the independent variable increases."

When x increases by 3, y decreases by 2

So the slope = rate of change of y / rate of change of x = -2/3

Given h(0)=2, h(0)=m(0)+c=2

c=2

Combining slope and y-intercept, y=-2/3*x+2

x-intercept is when y=0

0=-2/3*x+2

2/3*x=2

x=2*3/2=3

x-intercept=3

<em></em>

<em>BRAINLIEST</em>

4 0
3 years ago
Read 2 more answers
There are 60 seconds in a minute and 60 minutes in an hour. How many seconds are in one hour? *
Len [333]

Answer:

there are 3600 seconds in one hour

8 0
3 years ago
The half-life of carbon 14 is years. How much would be left of an original -gram sample after 2,292 years? (To the nearest whole
lozanna [386]

Answer:

A = 0.75 gram or 1 gram

Step-by-step explanation:

The half-life of carbon 14 is years. How much would be left of an original -gram sample after 2,292 years? (To the nearest whole number).

We can use the following formula for half-life of ^{14}C to find out how much is left from the original sample after 2,292 years:  

A = A_{0}e^{-0.000124t}

where:

<em>A</em> is the amount left of an original gram sample after <em>t</em> years, and  

A_{0} is the amount present at time <em>t</em> = 0.

The half-life of  ^{14}C  is the time <em>t</em> at which the amount present is one-half the amount at time <em>t </em>= 0.

If 1 gram of  ^{14}C is present in a sample,  

 Solve for A when t = 2,292:  

Substituting A_{0}  = 1 gram into the decay equation, and we have:  

A = A_{0}e^{-0.000124t}

A = A_{0}e^{-0.000124(2,292)}

A = 0.75 g or 1 g  

6 0
3 years ago
How do i solve this?
timofeeve [1]

Answer:

Measure the sides using a ruler and measure the angle using a protractor.

3 0
3 years ago
Please do all of these :)
wariber [46]
A SCATTER PLOT IS JUST A DOT PLOT
6 0
3 years ago
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