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3 years ago

½÷⅜

Mathematics

2 answers:

Talja [164]3 years ago

6 0

Answer: ½÷⅜ = 1 1/3

Step-by-step explanation:

Bye have a great life lol XP

valina [46]3 years ago

4 0

Answer:

Tiday: Sunday, 17th Jan 2021

4.13 PM

$\tt \frac{1}{2} \div \frac{3}{8}$

$\tt = \frac{1}{2} \times \frac{8}{3}$

$\tt = \frac{8}{6}$

$\tt = \frac{4}{3}$

$\tt {\boxed{\tt = \red{1 \frac{1}{3} }}}$

${\red{\boxed{\green{\boxed{ \pink{ \tt \: i \: hope \: this \: help}}}}}}$

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The braking distance, in feet of a car a Travling at v miles per hour is given.

irakobra [83]

The braking distance is the distance the car travels before coming to a stop after the brakes are applied

a. The braking distances are as follows;

The braking distance at 25 mph, is approximately 63.7 ft.

The braking distance at 55 mph, is approximately 298.35 ft.

The braking distance at 85 mph, is approximately 708.92 ft.

b. If the car takes 450 feet to brake, it was traveling with a speed of 98.211 ft./s

Reason:

The given function for the braking distance is D = 2.6 + v²/22

a. The braking distance if the car is going 25 mph is therefore;

25 mph = 36.66339 ft./s

$D = 2.6 + \dfrac{36.66339^2}{22} = 63.7 \ ft.$

At 25 mph, the braking distance is approximately 63.7 ft.

At 55 mph, the braking distance is given as follows;

55 mph = 80.65945 ft.s

$D = 2.6 + \dfrac{80.65945^2}{22} \approx 298.35 \ ft.$

At 55 mph, the braking distance is approximately 298.35 ft.

At 85 mph, the braking distance is given as follows;

85 mph = 124.6555 ft.s

$D = 2.6 + \dfrac{124.6555^2}{22} \approx 708.92 \ ft.$

At 85 mph, the braking distance is approximately 708.92 ft.

b. The speed of the car when the braking distance is 450 feet is given as follows;

$450 = 2.6 + \dfrac{v^2}{22}$

v² = (450 - 2.6) × 22 = 9842.8

v = √(9842.2) ≈ 98.211 ft./s

The car was moving at v ≈ 98.211 ft./s

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Yw = yw what is the reason

kotegsom [21]

Answer:

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Step-by-step explanation:

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Plz help me I have trouble with math gloves cost $48 and bats cost $35

34kurt

1 glove costs $48
5 gloves cost $240 (since 5*48 = 240)

1 bat costs $35
b bats cost 35*b dollars, where b is some positive whole number

The total cost of the bats and gloves is 35*b + 240. We simply add the subtotals (240 from the gloves and 35*b from the bats)

Plug in b = 3 and use PEMDAS to evaluate
35*b + 240
35*3 + 240 .... b has been replaced with 3
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To summarize:
The cost expression is 35*b + 240 (the cost is in dollars)
The total cost if the coach bought three bats is 345 dollars

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Answer:

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Trinomials can be factored into two sets of binomials. Always, sometimes, or never?

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