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cricket20 [7]
3 years ago
15

Simplify each ratio to lowest terms.

Mathematics
2 answers:
NeTakaya3 years ago
7 0

Answer:

ericyikaimiao said she/he is right

Vikki [24]3 years ago
3 0

Answer:

This is your work so i cant do it but I can give you a hint divide both the numerator and deomonator to get simplified form

Step-by-step explanation:

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26=2y-14 plz help out thxs :)
ASHA 777 [7]
26=2y-14\\
2y=40\\
y=20
5 0
3 years ago
Write 1/10^2 using exponents
Viefleur [7K]

Answer:

I think it would be 100

Step-by-step explanation:

because 10^2 is 10 x 10 which equals 100 and so if you have 1/10^2 it's basically saying 1 divided by 10^2 and 10^2 is 100 so it would be 1 divided by 100 which equals 100.

I hope this helped any.

4 0
4 years ago
A student carried out an experiment to determine the amount of vitamin C in a tablet sample. He performed 5 trials to produce th
ivolga24 [154]

Answer:

There is not enough evidence to support the claim that the amount of vitamin C in a tablet sample is different from 500 mg.

P-value = 0.166.

Step-by-step explanation:

We start by calculating the mean and standard deviation of the sample:

M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{5}(490+502+505+495+492)\\\\\\M=\dfrac{2484}{5}\\\\\\M=496.8\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{4}((490-496.8)^2+(502-496.8)^2+(505-496.8)^2+(495-496.8)^2+(492-496.8)^2)}\\\\\\s=\sqrt{\dfrac{166.8}{4}}\\\\\\s=\sqrt{41.7}=6.5\\\\\\

Then, we can perform the hypothesis t-test for the mean.

The claim is that the amount of vitamin C in a tablet sample is different from 500 mg.

Then, the null and alternative hypothesis are:

H_0: \mu=500\\\\H_a:\mu< 500

The significance level is 0.05.

The sample has a size n=5.

The sample mean is M=496.8.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=6.5.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{6.5}{\sqrt{5}}=2.907

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{496.8-500}{2.907}=\dfrac{-3.2}{2.907}=-1.1

The degrees of freedom for this sample size are:

df=n-1=5-1=4

This test is a left-tailed test, with 4 degrees of freedom and t=-1.1, so the P-value for this test is calculated as (using a t-table):

\text{P-value}=P(t

As the P-value (0.166) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the amount of vitamin C in a tablet sample is different from 500 mg.

4 0
3 years ago
5 is to 7 as is to 49
Ostrovityanka [42]
5 is to 7 as is to 49 is to 51
3 0
3 years ago
Can someone please help me please, I'll appreciate it:)
Alja [10]
It would be the third choice if ur rotating from point A
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