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cricket20 [7]
3 years ago
15

Simplify each ratio to lowest terms.

Mathematics
2 answers:
NeTakaya3 years ago
7 0

Answer:

ericyikaimiao said she/he is right

Vikki [24]3 years ago
3 0

Answer:

This is your work so i cant do it but I can give you a hint divide both the numerator and deomonator to get simplified form

Step-by-step explanation:

You might be interested in
A triangle has a base length of 14cm greater than its height . If the area of the triangle is 48cm^2, find the height of the tri
irga5000 [103]
Area of triangle = base x height /2
48 = (a+14)a/2
a^2 +14a = 96
a^2 + 14a - 96 = 0
Solving for a = 5.04
5 0
3 years ago
Will give brainliest i rlly need help
Zepler [3.9K]

Answer:

1/6

Step-by-step explanation:

-3/4 - (-1/2) = - 1/4

-2/3 - 5/6 = - 3/2

-1/4 ÷ -3/2

3 0
2 years ago
I neeeed helppppppp pleaseeee
Artist 52 [7]

Answer: 6144m^2

Step-by-step explanation:

4 0
3 years ago
How much of a radioactive kind of thorium will be left after 14,680 years if you start with
babymother [125]

Answer:

8978 grams

Step-by-step explanation:

The equation to find the half-life is:

N(t)= N_{0}e^{-kt}

N(t) = amount after the time <em>t</em>

N_{0} = initial amount of substance

t = time

It is known that after a half-life there will be twice less of a substance than what it intially was. So, we can get a simplified equation that looks like this, in terms of half-lives.

N(t)= N_{0}e^{-\frac{ln(\frac{1}{2}) }{t_{h} } t} or more simply N(t)= N_{0}(\frac{1}{2})^{\frac{1}{t_{h} } }

t_{h} = time of the half-life

We know that N_{0} = 35,912, t = 14,680, and t_{h}=7,340

Plug these into the equation:

N(t) = 35912(\frac{1}{2})^{\frac{14680}{7340} }

Using a calculator we get:

N(t) = 8978

Therefore, after 14,680 years 8,978 grams of thorium will be left.

Hope this helps!! Ask questions if you need!!

8 0
2 years ago
Evaluate the expression 4−(1−4)−2 =
Cloud [144]

Parentheses first. 1-4= -3. 4-3=1. 1-2=-1.

The answer is -1.

3 0
3 years ago
Read 2 more answers
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