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3 years ago

Simplify each ratio to lowest terms.

Mathematics

2 answers:

NeTakaya3 years ago

7 0

Answer:

ericyikaimiao said she/he is right

Vikki [24]3 years ago

3 0

Answer:

This is your work so i cant do it but I can give you a hint divide both the numerator and deomonator to get simplified form

Step-by-step explanation:

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NEED HELP FAST!!! 25 POINTS!

Yuki888 [10]

Answer:

0.55

Step-by-step explanation:

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3 years ago

A basketball coach keeps track of the points scored per game for all of her players. She gives a trophy to to the player with th

Andrei [34K]

Answer:

She wants to take unusually of the good and bad games into account

Step-by-step explanation:

Given that a basketball coach keeps track of the points scored per game for all of her players. A trophy is given to the player with the highest mean score at the end of the season.

Mean vs median:

Mean is the arithmetic average of all the entries while median is the middle entry after arranging in ascending order.

Median is not affected by extreme items but mean is very much affected by unusually high or low scores.

Here since the trophy is decided to be given to the highest mean score it is obvious that

She wants to take unusually of the good and bad games into account

Because of this only, mean is taken instead of median.

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3 years ago

Read 2 more answers

What is -9 to the-3/2 power with no decimals

nikdorinn [45]

Your answer is -1/27

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3 years ago

PLEASE HELP!!

erik [133]

$2.=c.\\\\2\sin4x\cos4x=2\sin(2\cdot4x)=2\sin8x\\\\Used:\\\sin2\alpha=2\sin\alpha\cos\alpha$

$1.=b.\\\\\csc x-\sin x=\dfrac{1}{\sin x}-\dfrac{\sin^2x}{\sin x}=\dfrac{1-\sin^2x}{\sin x}=\dfrac{\cos^2x}{\sin x}\\\\=\dfrac{\cos x\cos x}{\sin x}=\cos x\cdot\dfrac{\cos x}{\sin x}=\cos x\cot x\\\\Used:\\\csc x=\dfrac{1}{\sin x}\\\\\sin^2x+\cos^2x=1\to\cos^2x=1-\sin^2x\\\\\cot x=\dfrac{\cos x}{\sin x}$

$3.=a.\\\\\dfrac{\sin x-1}{\sin x+1}=\dfrac{\sin x-1}{\sin x+1}\cdot\dfrac{\sin x+1}{\sin x+1}=\dfrac{\sin^2x-1^2}{(\sin x+1)^2}=\dfrac{\sin^2x-1}{(\sin x+1)^2}\\\\=\dfrac{-(1-\sin^2x)}{(\sin x+1)^2}=\dfrac{-\cos^2x}{(\sin x+1)^2}\\\\Used:\\(a-b)(a+b)=a^2-b^2\\\\\sin^2x+\cos^2x=1\to \cos^2x=1-\sin^2x$

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3 years ago

H(1)=-35<br><br>h(n)=h(n-1)*2<br><br>h(3)=

Nastasia [14]

Answer:

Step-by-step explanation:

3 0

2 years ago