To get the answer to this problem, first we have to subtract the marked up cost to the cost of the product. So we first minus 25.3 and 22.25. When we do this, we will get a difference of 3.05. This is the profit that you will earn. So after that, we have to divide 3.05 and 25.30 to get the mark up percentage. When we do this, we will get an answer of 0.12. So in order to convert that into a percentage, we just have to multiply it by 100 and we will get 12%.
Answer:
? = 30
Step-by-step explanation:
If the triangles are similar, then the only way I see this working is the sides measuring 63 and 54 are corresponding. The sides measuring 56 and 48 are corresponding. That leaves the sides measuring 35 and ? corresponding.
Set up a proportion.
63/54 = 35/?
63? = 54 * 35
63? = 1890
? = 30
Answer
I) A job pays $15/hr with no bonus first day pay.
II) A job pays $15/hr with a $20 bonus first day pay.
Step-by-step explanation:
The y-intercepts would represent additional income that is added on to the base wage. It means it is what the worker would already earn (one-time), adding on to their standard pay.
Let X represent hours, and the y-intercept be what is mentioned above.
I) 15x + 0
II) 15x + 20
![\: \: \: \: \: \blue{\underline{\underline{ \large{ \tt{ \red{✧A \: N \: S \: W \: E \: R}}}}}}](https://tex.z-dn.net/?f=%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%5C%3A%20%20%5C%3A%20%20%20%20%20%5Cblue%7B%5Cunderline%7B%5Cunderline%7B%20%5Clarge%7B%20%5Ctt%7B%20%5Cred%7B%E2%9C%A7A%20%5C%3A%20N%20%5C%3A%20S%20%5C%3A%20W%20%5C%3A%20E%20%5C%3A%20R%7D%7D%7D%7D%7D%7D)
![\large{ \tt{✽ Step - By - Step \:Explanation}} :](https://tex.z-dn.net/?f=%20%5Clarge%7B%20%5Ctt%7B%E2%9C%BD%20%20Step%20-%20By%20-%20Step%20%5C%3AExplanation%7D%7D%20%3A%20)
![\underline{ \underline{ \large{ \tt{G \: I\: V \: E \: N}}} }:](https://tex.z-dn.net/?f=%20%5Cunderline%7B%20%5Cunderline%7B%20%5Clarge%7B%20%5Ctt%7BG%20%5C%3A%20I%5C%3A%20V%20%5C%3A%20E%20%5C%3A%20N%7D%7D%7D%20%7D%3A%20)
- C.P of two mobile set = Rs 55555
- Profit % on selling 1 mobile = 10%
- Loss % on selling another mobile = 10%
![\underline{ \underline{ \large{ \tt{S\: O \: L \:V \:I \: N \: G}} }}....](https://tex.z-dn.net/?f=%20%5Cunderline%7B%20%5Cunderline%7B%20%5Clarge%7B%20%5Ctt%7BS%5C%3A%20O%20%5C%3A%20L%20%5C%3AV%20%5C%3AI%20%5C%3A%20N%20%5C%3A%20G%7D%7D%20%7D%7D....)
![\begin{array}{ |c| c | } \tt{Case \: I}& \text{Case \: II} \\ \hline \hline \tt{CP = x} & \tt{ CP = 55555 - x} \\ \tt{Profit\% =10 } & \tt{Loss\% = 10\%} \\\ \tt{SP_{1} = \frac{cp(100 + P\%)}{100} }\\ & \tt{SP_{2} = \frac{cp(100 - L\%)}{100} }\\ = \tt{\frac{x(100 + 10)}{10} } & = \tt{\frac{9 \cancel{0}(55555 - x)}{1 \cancel{00}}} \\ \\ = \frac{11}{10} x & = \tt{\frac{499995 - 9x}{10}} \end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7B%20%20%7Cc%7C%20c%20%7C%20%7D%20%5Ctt%7BCase%20%5C%3A%20I%7D%26%20%5Ctext%7BCase%20%5C%3A%20II%7D%20%20%5C%5C%20%20%5Chline%20%5Chline%20%20%5Ctt%7BCP%20%3D%20x%7D%20%26%20%20%5Ctt%7B%20CP%20%3D%2055555%20-%20x%7D%20%5C%5C%20%20%5Ctt%7BProfit%5C%25%20%3D10%20%20%20%7D%20%20%26%20%5Ctt%7BLoss%5C%25%20%3D%2010%5C%25%7D%20%5C%5C%5C%20%20%20%5Ctt%7BSP_%7B1%7D%20%3D%20%20%20%5Cfrac%7Bcp%28100%20%2B%20P%5C%25%29%7D%7B100%7D%20%7D%5C%5C%20%20%20%20%26%20%20%20%5Ctt%7BSP_%7B2%7D%20%3D%20%20%5Cfrac%7Bcp%28100%20-%20L%5C%25%29%7D%7B100%7D%20%20%20%7D%5C%5C%20%20%20%3D%20%5Ctt%7B%5Cfrac%7Bx%28100%20%2B%2010%29%7D%7B10%7D%20%7D%20%20%26%20%20%3D%20%20%20%5Ctt%7B%5Cfrac%7B9%20%5Ccancel%7B0%7D%2855555%20-%20x%29%7D%7B1%20%5Ccancel%7B00%7D%7D%7D%20%20%5C%5C%20%20%5C%5C%20%3D%20%20%5Cfrac%7B11%7D%7B10%7D%20%20x%20%20%26%20%20%3D%20%20%20%5Ctt%7B%5Cfrac%7B499995%20-%209x%7D%7B10%7D%7D%20%5Cend%7Barray%7D%20%3C%2Fp%3E%3Cp%3E)
![\underline{ \large{ \tt{According \: To \:Question \: (ATQ)}} }:](https://tex.z-dn.net/?f=%20%5Cunderline%7B%20%5Clarge%7B%20%5Ctt%7BAccording%20%5C%3A%20To%20%5C%3AQuestion%20%5C%3A%20%28ATQ%29%7D%7D%20%7D%3A%20)
![\large{ \tt{ SP_{1} = SP_{2}}}](https://tex.z-dn.net/?f=%20%5Clarge%7B%20%5Ctt%7B%20SP_%7B1%7D%20%3D%20%20SP_%7B2%7D%7D%7D)
⤏ ![\large{ \tt{ \frac{11}{10} x = \frac{499995 - 9x}{10}}}](https://tex.z-dn.net/?f=%20%5Clarge%7B%20%5Ctt%7B%20%5Cfrac%7B11%7D%7B10%7D%20x%20%3D%20%20%5Cfrac%7B499995%20-%209x%7D%7B10%7D%7D%7D%20)
⤏ ![\large{ \tt{110x = 4999950 - 90x}}](https://tex.z-dn.net/?f=%20%5Clarge%7B%20%5Ctt%7B110x%20%3D%204999950%20-%2090x%7D%7D)
⤏ ![\tt{110x + 90x = 4999950}](https://tex.z-dn.net/?f=%20%5Ctt%7B110x%20%2B%2090x%20%3D%204999950%7D)
⤏ ![\large{ \tt{200x = 4999950}}](https://tex.z-dn.net/?f=%20%5Clarge%7B%20%5Ctt%7B200x%20%3D%204999950%7D%7D)
⤏ ![\large{ \tt{x = \frac{4999950}{200}}}](https://tex.z-dn.net/?f=%20%5Clarge%7B%20%5Ctt%7Bx%20%3D%20%20%5Cfrac%7B4999950%7D%7B200%7D%7D%7D%20)
⤏ ![\large{ \tt{x = 24999.97}}](https://tex.z-dn.net/?f=%20%5Clarge%7B%20%5Ctt%7Bx%20%3D%2024999.97%7D%7D)
![\large{ \tt{Replacing \: Value}} :](https://tex.z-dn.net/?f=%20%5Clarge%7B%20%5Ctt%7BReplacing%20%5C%3A%20Value%7D%7D%20%3A%20)
⤏ ![\large{ \tt{ SP = 2( \frac{11}{10 } \times 24999.97) = \underline{Rs \: 54999.934}}}](https://tex.z-dn.net/?f=%20%5Clarge%7B%20%5Ctt%7B%20SP%20%3D%202%28%20%5Cfrac%7B11%7D%7B10%20%7D%20%5Ctimes%2024999.97%29%20%3D%20%5Cunderline%7BRs%20%5C%3A%2054999.934%7D%7D%7D%20)
![\large{ \tt{CP = Rs \: 55555}}](https://tex.z-dn.net/?f=%20%5Clarge%7B%20%5Ctt%7BCP%20%3D%20Rs%20%5C%3A%2055555%7D%7D)
Since SP < CP , he / she made a loss
![\large{ \tt{Loss\% = \frac{CP- SP}{CP} \times 100\% }}](https://tex.z-dn.net/?f=%20%5Clarge%7B%20%5Ctt%7BLoss%5C%25%20%3D%20%20%5Cfrac%7BCP-%20SP%7D%7BCP%7D%20%20%5Ctimes%20100%5C%25%20%7D%7D)
⟶ ![\large \tt \: \frac{55555 - 54999.934}{55555} \times 100\%](https://tex.z-dn.net/?f=%20%5Clarge%20%5Ctt%20%5C%3A%20%20%5Cfrac%7B55555%20-%2054999.934%7D%7B55555%7D%20%20%5Ctimes%20100%5C%25)
⟶ ![\large{ \tt{0.99\%}}](https://tex.z-dn.net/?f=%20%5Clarge%7B%20%5Ctt%7B0.99%5C%25%7D%7D)
⟶![\boxed{ \large{ \tt{1\%}}}](https://tex.z-dn.net/?f=%20%5Cboxed%7B%20%5Clarge%7B%20%5Ctt%7B1%5C%25%7D%7D%7D)
Hence , Loss percent = 1%
Hope I helped ! ♕
Have a wonderful day / night ! ツ
✏
!!
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Hi there
The formula in this situation is
2=e^0.052t
Solve for t
T=(log(2)÷log(e))÷0.052
T=13.3 years round 13 years
Hope it helps