What is the circumference of this circle?

Solve the “and” compound inequality for –1 < 6x + 1 ≤ 13

ser-zykov [4K]

Answer:

-1/3 < x <(or equal to) 2

Step-by-step explanation:

Firstly divide your inequality into two separate inequalities...

1) -1 < 6x + 1...then solve for the first one..,which then gives you....;

-2 < 6x....which gives us our first solution (x > -1/3)

Then the second inequality

2) 6x + 1 <(or equal to) 13

which then gives you....,

6x <(or equal to) 12...which then gives our second solution...( x <(or equal to) 2)

Then combine the two solutions into a compound solution

-1/3 < x <(or equal to) 2

8 0

3 years ago

Before the pandemic cancelled sports, a baseball team played home games in a stadium that holds up to 50,000 spectators. When ti

spayn [35]

Answer:

(a) $D(x)=-2,500x+60,000$

(b) $R(x)=60,000x-2500x^2$

(c) x=12

(d)Optimal ticket price: $12

Maximum Revenue:$360,000

Step-by-step explanation:

The stadium holds up to 50,000 spectators.

When ticket prices were set at $12, the average attendance was 30,000.

When the ticket prices were on sale for $10, the average attendance was 35,000.

(a)The number of people that will buy tickets when they are priced at x dollars per ticket = D(x)

Since D(x) is a linear function of the form y=mx+b, we first find the slope using the points (12,30000) and (10,35000).

$\text{Slope, m}=\dfrac{30000-35000}{12-10}=-2500$

Therefore, we have:

$y=-2500x+b$

At point (12,30000)

$30000=-2500(12)+b\\b=30000+30000\\b=60000$

Therefore:

$D(x)=-2,500x+60,000$

(b)Revenue

$R(x)=x \cdot D(x) \implies R(x)=x(-2,500x+60,000)\\\\R(x)=60,000x-2500x^2$

(c)To find the critical values for R(x), we take the derivative and solve by setting it equal to zero.

$R(x)=60,000x-2500x^2\\R'(x)=60,000-5,000x\\60,000-5,000x=0\\60,000=5,000x\\x=12$

The critical value of R(x) is x=12.

(d)If the possible range of ticket prices (in dollars) is given by the interval [1,24]

Using the closed interval method, we evaluate R(x) at x=1, 12 and 24.

$R(x)=60,000x-2500x^2\\R(1)=60,000(1)-2500(1)^2=\$57,500\\R(12)=60,000(12)-2500(12)^2=\$360,000\\R(24)=60,000(24)-2500(24)^2=\$0$

Therefore:

Optimal ticket price:$12
Maximum Revenue:$360,000

3 0

3 years ago

You are having a discussion about sequences with your classmate. She insists that the sequence 2,3,5,8,12 must be a Arithmatic o

timofeeve [1]

<span>The arithmetic sequences have a constant difference between two terms. This sequence does not match this criterion, look: 12-8 = 4; 8-5=3; 5-3=2. Then it is not arithmetic. Let's examine whether it is geometric. Geometric sequences have a constant ration between adjacent terms: given that 3/2 is different to 5/3, and both are different to 8/5 and so on, this sequence does not either match this requirement. Then the sequence is not arithmetic or geometric.</span>

4 0

3 years ago

Write 4x2(–2x2 + 5x3) in standard form. Then classify it by degree and number of terms.

umka2103 [35]

$20x^5-8x^4$ polynomial of the 5th degree, with two terms.

Distribute 4x^2(–2x^2 + 5x^3) to get –8x^2 + 20x^5. Reorder in standard form 20x^5-8x^4. 5 is the highest exponent so it is the 5th degree, there are two terms because terms are separated by a plus or minus.

3 0

3 years ago

In parallelogram DEFG, DH = x + 2, HF = 2y, GH = 3x – 3, and HE = 5y + 1. Find the values of x and y. x = 10, y = 18 x = 18, y =

strojnjashka [21]

Answer:

I think The answer to your question is 10

Step-by-step explanation:

8 0

3 years ago

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