Answer:
256/3 = 85 1/3 square inches
Step-by-step explanation:
The dimensions of the first inscribed triangle are 1/2 those of the original, so its area is (1/2)² = 1/4 of the original. The area of the original is ...
A = (1/2)bh = (1/2)(16/√2)(16/√2) = 64 . . . . square inches
The sum of an infinite series with first term 64 and common ratio 1/4 is ...
S = a1/(1 -r) . . . . . . for first term a1 and common ratio r
= 64/(1 -1/4) = 64(4/3) = 256/3 . . . . square inches
The sum of the areas of the triangles is 256/3 = 85 1/3 square inches.
14+5x=3(-x+3)-11
14+5x=-3x+9-11
14+5x=-3x-2
add 2 to both sides
16+5x=-3x
subtract 5x from both sides
16=-8x
divide both sides by -8
-2=x
Hope this helps! :)
Thousands grou
the thousands group. 913,256 256 being the ones group 913 being the thousands group. the name of the period with 913, is the thousands group p
Answer:
Step-by-step explanation:
we need the problems to solve so erm yeah can you like tell me them please but to solve triangles you have to find the angles. hope i helped a bit
Answer:
x²-12x+36
Step-by-step explanation:
