5
------------
15
kinda looks like division
5 numerator
----- division line
15 denominator
how many time does 5 go into 15?
3 times
3
----
5
Answer:
1) Combine the x tiles to get: ![\mathbf{4x}](https://tex.z-dn.net/?f=%5Cmathbf%7B4x%7D)
2) Combine integer tiles to get: 3
3) The equivalent function is: ![\mathbf{4x+3}](https://tex.z-dn.net/?f=%5Cmathbf%7B4x%2B3%7D)
4) If we Substitute any value of x both expressions will be equivalent
Step-by-step explanation:
We are given expression: ![x+x+x+x++4-1\\](https://tex.z-dn.net/?f=x%2Bx%2Bx%2Bx%2B%2B4-1%5C%5C)
We need to complete following statements.
1) Combine the x tiles to get:
![x+x+x+x\\=4x](https://tex.z-dn.net/?f=x%2Bx%2Bx%2Bx%5C%5C%3D4x)
Combine the x tiles to get: ![\mathbf{4x}](https://tex.z-dn.net/?f=%5Cmathbf%7B4x%7D)
2) Combine integer tiles to get:
![+4-1\\=3](https://tex.z-dn.net/?f=%2B4-1%5C%5C%3D3)
Combine integer tiles to get: 3
3) The equivalent function is:
![x+x+x+x++4-1\\\\4x+3](https://tex.z-dn.net/?f=x%2Bx%2Bx%2Bx%2B%2B4-1%5C%5C%5C%5C4x%2B3)
The equivalent function is: ![\mathbf{4x+3}](https://tex.z-dn.net/?f=%5Cmathbf%7B4x%2B3%7D)
4) If we Substitute any value of x both expressions will be equivalent
Verifying:
![x+x+x+x+4-1=4x+3\\Let\: x = 1\\1+1+1+1+4-1=4(1)+3\\4+4-1=4+3\\7=7](https://tex.z-dn.net/?f=x%2Bx%2Bx%2Bx%2B4-1%3D4x%2B3%5C%5CLet%5C%3A%20x%20%3D%201%5C%5C1%2B1%2B1%2B1%2B4-1%3D4%281%29%2B3%5C%5C4%2B4-1%3D4%2B3%5C%5C7%3D7)
So, Both expressions are equivalent.
Every hexagon clearly has 6 sides. Nevertheless, every time you "glue" two hexagons together, you "lose" 2 sides to your count, because the sides where the two hexagons meet are not exterior sides anymore, and so they are not taken into account in our counting.
Also observe that with n hexagons you have n-1 points of contact between hexagons.
Since every hexagon has 6 sides and every gluing point takes away 2 sides, the number of exterior sides with n hexagons is
![s(n)=6n - 2(n-1) = 6n-2n+2=4n+2](https://tex.z-dn.net/?f=s%28n%29%3D6n%20-%202%28n-1%29%20%3D%206n-2n%2B2%3D4n%2B2)
Let's plug some values for n:
You can check that these values are correct by counting the sides on the figure you have.
Finally, we can count the sides of a train with 10 hexagons by plugging n=10 in our formula:
![s(10) = 4\cdot 10 + 2 = 40 + 2 = 42](https://tex.z-dn.net/?f=s%2810%29%20%3D%204%5Ccdot%2010%20%2B%202%20%3D%2040%20%2B%202%20%3D%2042)
Note: the numbers we've given are the number of sides that form the perimeter. So, the actual perimeters are the number of sides multiplied by the length of the side itself: if we let
be the length of the side, the perimeters will be
for the first 4 trains, and
for the 10-hexagon train.
Answer:
c
Step-by-step explanation:
The fraction computed indicates that the amount donated will be $2000000.
<h3>How to calculate the fraction</h3>
Your information is incomplete. Therefore, an overview will be given.
In this case, let's assume that the profit is 3,000,000. Therefore, the amount that is donated will be:
= 2/3 × $3000000
= $2000000
Learn more about fractions on:
brainly.com/question/786722