The unit normal for the given plane is <5,2,-1>.
The equation of the plane parallel to the given plane passing through (5,5,4) is therefore
5(x-5)+2(y-5)-1(z-4)=0
simplify =>
5x+2y-z=25+10-4=31
Answer: the plane through (5,5,4) parallel to 5x+2y-z=-6 is 5x+2y-z=31
I don't understand the question
Answer:

Step-by-step explanation:
The first line has a slope of -5/3 found using the points in the slope formula.

Parallel lines have the same slope. So -5/3 is the slope of the second line. Write its equation using the point slope form
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