5x+2y=27.50 2x+5y=33.00

2 answers:

5 0

Answer:
x = 3.405; y = 5.238

Steps:
1.) cancel out the x’s
2(5x+2y=27.50) -5(2x+5y=33.00)
10x+4y=55 -10x-25y=-165

2.) solve the equation and subtract them
10x+4y=55
-10x-25y=-165
———————
-21y=-110

3.) divide -21 by -110 to isolate the y
-21/-110=5.238 (about)
y=5.238

4.) plug y back into one of the equations
2x+5(5.238)=33.00

5.) solve for x
2x+26.19=33.00
-26.19 -26.19
—————————
2x=6.81

6.) divide 2 by 6.81
2/6.81=3.405
x=3.405

Charra [1.4K]3 years ago

3 0

Answer:

what is the question?

Step-by-step explanation:

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noname [10]

Answer:

$\boxed{\text{A. }\math{\left \{ x \, | \, x \in \mathbb{R}, x < -2 \right \}}}}$

Step-by-step explanation:

The open circle means that the point is not included in the solution set, and the arrow pointing left means that all numbers less than -2 are members.

In set-builder notation, each term has a special meaning. The braces enclose the members of the set.

Here's how you translate the notation,

$\begin{array}{rcl}\\\left \{ & = & \text{The set of}\\x & = & \text{all x values}\\| & = &\text{such that}\\x & = & x\\\in & = &\text{is a member of}\\\mathbb{R}, & = &\text{all real numbers, and}\\x < -2 & = & \text{x is less than -2}\\\end{array}\\\text{The answer is }\boxed{\textbf{A. }\mathbf{\left \{ x \, | \, x \in \mathbb{R}, x < -2 \right \} }}}$