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olganol [36]
3 years ago
12

The students at a school are voting on their favorite type of music. Charles surveys a representative sample of students to dete

rmine for which type of music each student will vote. The results are in the table below.
STUDENT VOTES
Type of Music Number of Votes
Hip Hop 21
Jazz 15
Classic Rock 9
Punk 6
Charles thinks that if all 850 students vote, 355 students will vote for jazz.

By how many students is his prediction off?

Enter your answer in the box.
Mathematics
1 answer:
Tpy6a [65]3 years ago
5 0
Wait wouldn’t it just be subtracting 355 from 15 cause if so your answer is 340 but I’m not to sure
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Step-by-step explanation:

-5+2+6x

-5+2= -3

-3+6x

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Are American miles the same distance as U.K. miles?
MatroZZZ [7]

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yes they are

Step-by-step explanation:

because the metric system is the same

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The greatest rate of rainfall in Europe was 14.4
pickupchik [31]

Answer:

5.76 inches. You can round this if you want.

Step-by-step explanation:

14.4 divide by 2 is 5.76

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4 years ago
Combine into a single logarithm.<br><br> 3log(x+y)+2log(x-y)-log(x^2 +y^2)
seropon [69]

Answer:

3\log _{10}\left(x+y\right)+2\log _{10}\left(x-y\right)-\log _{10}\left(x^2+y^2\right)=\log _{10}\left(\frac{\left(x+y\right)^3\left(x-y\right)^2}{x^2+y^2}\right)

Step-by-step explanation:

Given the expression

3log\left(x+y\right)+2log\left(x-y\right)-log\left(x^2\:+y^2\right)

solving to write into a single logarithm

3log\left(x+y\right)+2log\left(x-y\right)-log\left(x^2\:+y^2\right)

  • \mathrm{Apply\:log\:rule}:\quad \:a\log _c\left(b\right)=\log _c\left(b^a\right)

3\log _{10}\left(x+y\right)=\log _{10}\left(\left(x+y\right)^3\right)

so

=\log _{10}\left(\left(x+y\right)^3\right)+2\log _{10}\left(x-y\right)-\log _{10}\left(x^2+y^2\right)

  • \mathrm{Apply\:log\:rule}:\quad \:a\log _c\left(b\right)=\log _c\left(b^a\right)

2\log _{10}\left(x-y\right)=\log _{10}\left(\left(x-y\right)^2\right)

so

=\log _{10}\left(\left(x+y\right)^3\right)+\log _{10}\left(\left(x-y\right)^2\right)-\log _{10}\left(x^2+y^2\right)

  • \mathrm{Apply\:log\:rule}:\quad \log _c\left(a\right)+\log _c\left(b\right)=\log _c\left(ab\right)

\log _{10}\left(\left(x+y\right)^3\right)+\log _{10}\left(\left(x-y\right)^2\right)=\log _{10}\left(\left(x+y\right)^3\left(x-y\right)^2\right)

so

=\log _{10}\left(\left(x+y\right)^3\left(x-y\right)^2\right)-\log _{10}\left(x^2+y^2\right)

  • \mathrm{Apply\:log\:rule}:\quad \log _c\left(a\right)-\log _c\left(b\right)=\log _c\left(\frac{a}{b}\right)

\log _{10}\left(\left(x+y\right)^3\left(x-y\right)^2\right)-\log _{10}\left(x^2+y^2\right)=\log _{10}\left(\frac{\left(x+y\right)^3\left(x-y\right)^2}{x^2+y^2}\right)

=\log _{10}\left(\frac{\left(x+y\right)^3\left(x-y\right)^2}{x^2+y^2}\right)

Thus,

3\log _{10}\left(x+y\right)+2\log _{10}\left(x-y\right)-\log _{10}\left(x^2+y^2\right)=\log _{10}\left(\frac{\left(x+y\right)^3\left(x-y\right)^2}{x^2+y^2}\right)

6 0
3 years ago
Help me solve this problem from kahn academy
S_A_V [24]

Answer:

150

Step-by-step explanation:

Angle A= angle b

8x-10=3x+90

5x=100

x=20

Angle B=150

6 0
3 years ago
Read 2 more answers
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