The pentagon is the one with 5 sides. Good Luck!
Yes, you can; based on the inherent assumption that the "two radicals that have negative values" are, in fact, "imaginary numbers" .
Take, for example, the commonly known "imaginary number": "i" ; which represents the "imaginary number" ; " √-1 " .
Since: "i = √-1" ;
Note that: " i² = (√-1)² = √-1 * √-1 = √(-1*-1) = √1 = 1 .
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In this item, we are to calculated for the 6th term of the geometric sequence given the initial value and the common ratio. This can be calculated through the equation,
An = (A₀)(r)ⁿ ⁻ ¹
where An is the nth term, A₀ is the first term (in this item is referred to as t₀), r is the common ratio, and n is the number of terms.
Substitute the known values to the equation,
An = (5)(-1/2)⁶ ⁻ ¹
An = -5/32
Hence, the answer to this item is the third choice, -5/32.
Answer:
18
Step-by-step explanation:
<em>Convert</em><em> </em><em>the</em><em> </em><em>mixed</em><em> </em><em>number</em><em> </em><em>to</em><em> </em><em>an</em><em> </em><em>improper</em><em> </em><em>fraction</em><em> </em><em>9</em><em>/</em><em>2</em><em>÷</em><em>1</em><em>/</em><em>4</em>
<em>Reduce</em><em> </em><em>the</em><em> </em><em>numbers</em><em> </em><em>with</em><em> </em><em>the</em><em> </em><em>greatest</em><em> </em><em>common</em><em> </em><em>factor</em><em> </em><em>2</em><em> </em>
<em>and</em><em> </em><em>then</em><em> </em><em>multiply</em><em> </em><em>the</em><em> </em><em>numbers</em><em> </em><em>9</em><em>×</em><em>2</em><em>=</em><em>18</em><em> </em><em>✅</em>
There is no solution to this system of linear equations
