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ANTONII [103]
3 years ago
10

What is the factored form of 24y^5 + 3y^2?

Mathematics
1 answer:
Dmitry [639]3 years ago
3 0
Common factor

24y^5+3y^2

3(8y^5+y^2)


Solution

3y^2(2y+1)(4y^2-2y+1)
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Noah is solving an equation, and one of his moves is unacceptable. Here are the moves he made.
faust18 [17]

Answer:

b. When you divide both sides by 2x = 6x it could lead us to think that there is no solution while, in fact, the solution is x = 0.

Step-by-step explanation:

The solution is correct up to the step 2x = 6x

2x = 6x

Subtract 2x from both sides.

0 = 4x

Divide both sides by 4.

x = 0

You cannot divide both sides by x since x could be zero, and in fact, it is.

Answer: b. When you divide both sides by 2x = 6x it could lead us to think that there is no solution while, in fact, the solution is x = 0.

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I need help with this question 1/2 + 2 3/4=?
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Answer:

3.25

Step-by-step explanation:

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3 years ago
Solve the system of equations by graphing: 2x + 3y = 2 6x + 18y = 9
cluponka [151]
The answer is  A: x=1/2 , y= 1/3

Solve the following system:
{2 x + 3 y = 2 | (equation 1)
{6 x + 18 y = 9 | (equation 2)

Swap equation 1 with equation 2:
{6 x + 18 y = 9 | (equation 1)
{2 x + 3 y = 2 | (equation 2)

Subtract 1/3 × (equation 1) from equation 2:
{6 x + 18 y = 9 | (equation 1)
{0 x - 3 y = -1 | (equation 2)

Divide equation 1 by 3:
{2 x + 6 y = 3 | (equation 1)
{0 x - 3 y = -1 | (equation 2)

Multiply equation 2 by -1:
{2 x + 6 y = 3 | (equation 1)
{0 x+3 y = 1 | (equation 2)

Divide equation 2 by 3:
{2 x + 6 y = 3 | (equation 1)
{0 x+y = 1/3 | (equation 2)

Subtract 6 × (equation 2) from equation 1:
{2 x+0 y = 1 | (equation 1)
v0 x+y = 1/3 | (equation 2)

Divide equation 1 by 2:
{x+0 y = 1/2 | (equation 1)
v0 x+y = 1/3 | (equation 2)

Collect results:
Answer:  {x = 1/2, y = 1/3

7 0
3 years ago
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Nimfa-mama [501]
It would be = because they shipped the same amount in each year
8 0
3 years ago
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GuDViN [60]

Answer:106.63%.

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