Within a gymnosperm megasporangium, the following developmental sequences that are correct, assuming fertilization occurs is: megaspore, female gametophyte, egg cell, sporophyte embryo. The last Option (Option D) is correct.
In gymnosperm megasporangium, the meiotic division produces four haploid megaspores from a single cell, three of which generally degenerate. The female gametophyte is formed by mitosis from the surviving megaspore.
Prior to fertilization, the male mature gametophyte needs to be transferred to the female gametophyte for fertilization to take place.
When the nuclei of the sperm encounter the nucleus of the egg cell in gymnosperms, it fuses with the egg nucleus to produce a diploid zygote.
Mitosis occurs in the fertilized egg to initiate the growth of a new sporophyte generation (the multicellular embryo of the seed.)
Therefore, we can conclude that we've understood the mechanism of developmental sequence in the gymnosperm megasporangium.
Learn more about the gymnosperm here:
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Is this problem multiple choice? I remember much of biology but I'm blanking on vocab
Answer:
Due to insulin resistance, it is a bit hard for their body to naturally break down glucose(<em>a form of sugar</em>) like a normal body would.
It is the Light-Dependent stage of photosynthesis that occurs on the membrane or in the lumen of the Thylakoid. It is the Thylakoid that houses the photosystems and the photosynthetic pigments that are responsible for the trapping of light and its subsequent manipulation to produce energy for Light-independent stage to occur.
