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3 years ago

32 3/4−12 1/2=

Mathematics

1 answer:

makkiz [27]3 years ago

7 0

Ans: 20.25

can convert the mixed numbers fractions to improper fractions before making the denominators the same and coming up with the answer in decimals

hope this helps:))

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K divided by 11 equals seven what is k

Irina18 [472]

Answer:

Step-by-step explanation:

k/11=7

7x11=k

k=77

8 0

3 years ago

If a photocopier makes copies in 1/3 s, then at the same rate, how many copies does it make in 4 minutes?

irina1246 [14]

Answer:

80 copies

Step-by-step explanation:

4 minutes= 240 seconds. So I did 240 seconds divided by 3 seconds (one copy is made in that time) then you get 80. I don't know if that explanation make sense but the math checks out.

3 0

3 years ago

8. Mason bought a pair of running shoes for $36.98. If the sales tax is 6.5%, how much

serg [7]

Answer:

$39.38

Step-by-step explanation:

$36.98 * 6.5%= 2.4037

2.4037 + 36.98= 39. 3837

round up

$39.38

6 0

3 years ago

The height (feet) of an object moving vertically is given by s= (-16t^2)+(208t)+(156), where t is in seconds.

OverLord2011 [107]

Answer:

The object's velocity at t = 7 is -16 ft/s

The maximum height is 832 ft and it occurs when $t=\frac{13}{2}$

Step-by-step explanation:

From the information given, the equation of motion of the object is

$s(t)= -16t^2+208t+156$

For any equation of motion s(t), the instantaneous velocity at time t is given by

$v(t)=\frac{ds}{dt}$

(a) To find the object's velocity at t = 7, you must:

$v(t)=\frac{d}{dt}(-16t^2+208t+156)\\\\v(t)=-\frac{d}{dt}\left(16t^2\right)+\frac{d}{dt}\left(208t\right)+\frac{d}{dt}\left(156\right)\\\\v(t)=-32t+208+0\\\\v(t)=-32t+208$

Next, we evaluate when t = 7

$v(7)=-32(7)+208=-224+208\\\\v(7)=-16$

The object's velocity at t = 7 is -16 ft/s

(b) <em>To find the maximum of a function we always use the derivative of the function and we set it equal zero to find the</em><em> critical points.</em>

To find the maximum height and when it occurs, we set the velocity function equal to 0 and solve for t.

$-32t+208=0\\\\-32t+208-208=0-208\\\\-32t=-208\\\\\frac{-32t}{-32}=\frac{-208}{-32}\\\\t=\frac{13}{2}$

Next, we substitute this value into the equation of motion to find the maximum height

$s(\frac{13}{2})= -16(\frac{13}{2})^2+208(\frac{13}{2})+156\\\\s(\frac{13}{2})=-676+1352+156)=832$

The maximum height is 832 ft and it occurs when $t=\frac{13}{2}$

6 0

3 years ago

Plz help on the 6 problems

Leokris [45]

1.) 9
2.)7
3.)106
4.)13
5.)192
6.)11

5 0

3 years ago