option A.55°
Answer:
Solution given:
<x+<y=<z
exterior angle of a triangle is equal to the sum of two opposite interior angle
4n-18+n+8=133-6n
5n+6n=133+10
11n=143
n=143/11
n=13
<u>exterior</u><u> </u><u>angle</u><u> </u><u>=</u><u>1</u><u>3</u><u>3</u><u>-</u><u>6</u><u>*</u><u>1</u><u>3</u><u>=</u><u>5</u><u>5</u><u>°</u>
<u>option</u><u> </u><u>A</u><u>.</u><u>5</u><u>5</u><u>°</u>
Remember PEMDAS (Parenthesis, Exponents, Multiplication, Divison, Addition and Subtraction)
Also note that Multiplication and Division needs to be done left to right and the same goes for Addition and Subtraction.
So in your problem, the first operation we need to do is division.
68 - (18/3) x 6
68 - 6 x 6
Now we do multiplication
68 - 6 x 6
68 - 36
Finally we do subtraction because that's the only operation we have left to do
68 - 36 = 32
So your answer should be 32.
Answer:
I think it would be C. that would be my answer
Five exterior angles of a hexagon are 41° 32°,67º 71°, and 55°, What is the measure of the sixth exterior
angle?
Can yo help me w this pls
You can write 20/10 as a mixed number by dividing 20 by 10 and you 2 as your answer.
So, Your answer will be 2.
Hope that helped.
