Answer is 14 I think pretty sure hope so yeah
Answer:
2(d-vt)=-at^2
a=2(d-vt)/t^2
at^2=2(d-vt)
Step-by-step explanation:
Arrange the equations in the correct sequence to rewrite the formula for displacement, d = vt—1/2at^2 to find a. In the formula, d is
displacement, v is final velocity, a is acceleration, and t is time.
Given the formula for calculating the displacement of a body as shown below;
d=vt - 1/2at^2
Where,
d = displacement
v = final velocity
a = acceleration
t = time
To make acceleration(a), the subject of the formula
Subtract vt from both sides of the equation
d=vt - 1/2at^2
d - vt=vt - vt - 1/2at^2
d - vt= -1/2at^2
2(d - vt) = -at^2
Divide both sides by t^2
2(d - vt) / t^2 = -at^2 / t^2
2(d - vt) / t^2 = -a
a= -2(d - vt) / t^2
a=2(vt - d) / t^2
2(vt-d)=at^2
Answer:
y=-x-8
Step-by-step explanation:
2x+2y=-16
2x+2y+16=0
2x+16=-2y
x+8=-y
-x-8=y
Answer:
(2y−1)(y−7)
Step-by-step explanation:
1) 2y^2-y-14y+7
2) y(2y−1)−7(2y−1)
3) (2y−1)(y−7)
9x^2-81=0
add 81 to each side
9x^2 = 81
divide by 9
x^2 =9
take the square root of each side
x = + - sqrt (9)
x=+3,-3
Choices D,E
