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AVprozaik [17]
3 years ago
13

Which of the followers scatter plots could have a trend line with an equation of 2x+5

Mathematics
2 answers:
Valentin [98]3 years ago
8 0

Answer:

answer is c   because   of the y intercept  . . so the y intercept is postive and goes through the orgin

Step-by-step explanation:

Mice21 [21]3 years ago
4 0
C
Hope this really helps you
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Solve the system.<br> 2x + y = −3 −2y = 6 + 4x<br> Write each equation in slope-intercept form.
Fantom [35]

The slope-intercept form:

y = mx + b

m - slope

b - y-intercept

-------------------------------------

2x + y = -3       <em>subtract 2x from both sides</em>

y = -2x - 3


-2y = 6 + 4x

-2y = 4x + 6     <em>divide both sides by (-2)</em>

y = -2x - 3

We have the same equations. Therefore the system of equations is dependent. Has an infinite number of solutions

x ∈ R

y = -2x - 3

7 0
4 years ago
Read 2 more answers
Please help me to solve this . Thank you so much .
worty [1.4K]

Answer:

a) N

b) L

c) area I

d) area II

e) area VI

Step-by-step explanation:

a) the points that are 2cm from R are Q, N, M, S. Then, points that are 4cm from P are K, N, R. So, the only one point that works for both is N.

b) the points that are >2cm from R are P, K, L, T. We do not count those are exactly 2cm from R. Then, points that are 4cm from T are R, M, L. Ans is L.

c) <4cm from P, are area I and II. Then area that are >2cm from R are I, VI, and V. So, the only area that works for both is I.

d) <2cm from R, are areas II, III, and IV. Then, <4cm from P, are areas I and II. So, the only one works for both is area II.

e) >4cm from T, are areas I, II, III, VI. Then, >4cm from P, are III, IV, V, VI. Finally, >2cm from R, are areas I, VI, V. The only one that works for all three conditions is area VI.

5 0
4 years ago
Area between two shapes. Pls help geometry IXL !
fenix001 [56]

Step-by-step explanation:

Area of shaded region = area of exterior rectangle - area of interior rectangle

37 \times 28 - 11 \times 20 \\  \\  = 1,036 - 220 \\  \\  = 816 \:  {yards}^{2}  \\

4 0
3 years ago
Read 2 more answers
Determine the quadrant and the coordinates of the given points.
polet [3.4K]
A: (-4,1), B(1,-3), C(0,2), D(5,0), E(-3,6) F(-4,-5), G(0,-4), H(2,4) I(-2,3), J(5,-2)
Quadrant 1: D, H
Quadrant 2: A, I, E
Quadrant 3: F
Quadrant 4: B, J
on the x axis: D
On the y axis: G, C
8 0
2 years ago
Solve the inequality −4y + 6 &lt; −14.
timama [110]

Answer:

y >5

Step-by-step explanation:

−4y + 6 < −14

Subtract 6 from each side

−4y + 6-6 < −14-6

-4y < -20

Divide by -4.  Remember to flip the inequality since we are dividing by a negative

-4y/-4 >-20/-4

y >5

5 0
3 years ago
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