I need help plz and thank you

some kangaroos can jump over 30 feet in one jump! if a kangaroo could jump like that 150 times in the row, how much farther woul

slega [8]

The answer is 780 feet.
There is 5,280 feet in a mile. If the kangaroo jumps 30 feet 150 times, it will have gone 4,500 feet. So the kangaroo will need to go 780 feet to make a mile.
Formula: 5,280-4,500=780

4 0

4 years ago

Answer this math question for 15 points please

Sergio [31]

Answer:

.......

Step-by-step explanation:

5 0

3 years ago

Part A. Let $f(x) = x^4-3x^2 + 2$ and $g(x) = 2x^4 - 6x^2 + 2x -1$. Let $a$ be a constant. What is the largest possible degree o

Varvara68 [4.7K]

Answer:

A. 4

B. 1

Step-by-step explanation:

The degree of a one-variable polynomial is the largest exponent of the variable.

__

For f(x) = x^4 -3x^2 +2 and g(x) = 2x^4 -6x^2 +2x -1, the sum f(x) +a·g(x) will be ...

(x^4 -3x^2 +2) +a(2x^4 -6x^2 +2x -1)

= (1 +2a)x^4 +(-3-6a)x^2 +2ax -a

The term with the largest exponent is (1 +2a)x^4, which has degree 4. This term will be non-zero for a ≠ -1/2.

The largest possible degree of f+ag is 4.

__

The polynomial sum is ...

f+bg = (1 +2b)x^4 +(-3-6b)x^2 +2bx -b

When b = -1/2, the first two terms disappear and the sum becomes ...

f+bg = -x +1/2 . . . . . . a polynomial of degree 1

The smallest possible degree of f+bg is 1.

5 0

3 years ago

A real estate agent has 17 properties that she shows. She feels that there is a 50% chance of selling any one property during a

Likurg_2 [28]

Answer:

0.0011 = 0.11% probability of selling less than 3 properties in one week.

Step-by-step explanation:

For each property, there are only two possible outcomes. Either they are sold, or they are not. The chance of selling any one property is independent of selling another property. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

A real estate agent has 17 properties that she shows.

This means that $n = 17$

She feels that there is a 50% chance of selling any one property during a week.

This means that $p = 0.5$

Compute the probability of selling less than 3 properties in one week.

This is

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{17,0}.(0.5)^{0}.(0.5)^{17} \approx 0$

$P(X = 1) = C_{17,1}.(0.5)^{1}.(0.5)^{16} = 0.0001$

$P(X = 2) = C_{17,2}.(0.5)^{2}.(0.5)^{15} = 0.0010$

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0 + 0.0001 + 0.0010 = 0.0011$

0.0011 = 0.11% probability of selling less than 3 properties in one week.

5 0

3 years ago

I need answer on this graphing va substitution.Problem 7 I tried to solve it but not sure that’s correct

Bond [772]

Given the system of equations:

$\begin{gathered} 2x+9y=27 \\ x-3y=-24 \end{gathered}$

To solve it by substitution, follow the steps below.

Step 1: Solve one linear equation for x in terms of y.

Let's choose the second equation. To solve it for x, add 3y to each side of the equations.

$\begin{gathered} x-3y=-24 \\ x-3y+3y=-24+3y \\ x=-24+3y \end{gathered}$

Step 2: Substitute the expression found for x in the first equation.

$\begin{gathered} 2x+9y=27 \\ 2\cdot(-24+3y)+9y=27 \\ -48+6y+9y=27 \\ -48+15y=27 \end{gathered}$

Step 3: Isolate y in the equation found in step 2.

To do it, first, add 48 to both sides.

$\begin{gathered} -48+15y=27 \\ -48+15y+48=27+48 \\ 15y=75 \end{gathered}$

Then, divide both sides by 15.

$\begin{gathered} \frac{15y}{15}=\frac{75}{15} \\ y=5 \end{gathered}$

Step 4: Substitute y by 5 in the relation found in step 1 to find x.

$\begin{gathered} x=-24+3y \\ x=-24+3\cdot5 \\ x=-24+15 \\ x=-9 \end{gathered}$

Answer:

x = -9

y = 5

or (-9, 5)

Also, you can graph the lines by choosing two points from each equation, according to the picture below.

7 0

1 year ago