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Naily [24]
2 years ago
13

Find sine, cosine, and tangent of theta: 0 = 240°

Mathematics
1 answer:
kumpel [21]2 years ago
7 0

Answer:

sin=0.945

cos=0.325

tan=2.902

Step-by-step explanation:

In a scientific calculator you simply enter "240°" then press cos/sin/tan after the degrees.

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!!!!!!!!!!!25 POINTS!!!!!!!!!!!
Otrada [13]

Answer:

adjacent, supplementary

Step-by-step explanation:

"Two lines intersecting in a right angle with a square indicating a right angle in quadrant one and a ray splitting quadrant two with a two labeling the left angle and one labeling the angle on the right"

Based on your description, it seems like they are right next to each other and equal 180 (straight line)

Angles directly next to each other = adjacent

Angles that add up to 180 = supplementary

This indicates adjacent and supplementary angles

7 0
1 year ago
I don't get this question #3
Alenkinab [10]
I am not 100% positive.
10 teams play every other ( = 5) once
10 x 5 = 50 games total
5 0
3 years ago
Answer in standard form PLEASE.
matrenka [14]

0.9 x 10^4

Let’s break this down into steps.

So to start off with, you need to do 4.5/5 which = 0.9.

Now we can deal with the indices. 10^-3 / 10^-7 means we have to subtract them. Therefore, -3 - -7 = 4. Altogether, we have 0.9 x 10^4

The question states we should leave our answer in standard form.

So our answer is 0.9 x 10^4.
8 0
2 years ago
A study in your town found that 54 in 1,762 people have a post office box what percent of the people in town have a post office
gavmur [86]
Multiply 54 times 100 then divide by 1,762

54 times 100= 5400

5400\1,762= .03

which equals to 3%
4 0
3 years ago
Show how to find the roots (zeros) of the function in the picture below.
Vikki [24]

Answer:

The roots (zeros) of the function are:

x=5,\:x=-8

Step-by-step explanation:

Given the function

f\left(x\right)=x^2+3x-40

substitute f(x) = 0 to determine the zeros of the function

0=x^2+3x-40

First break the expression x² + 3x - 40  into groups

x² + 3x - 40 = (x² - 5x) + (8x - 40)

Factor out x from x² - 5x:  x(x - 5)

Factor out 8 from 8x - 40:  8(x - 5)

Thus, the expression becomes

0=x\left(x-5\right)+8\left(x-5\right)

switch the sides

x\left(x-5\right)+8\left(x-5\right)=0

Factor out common term x - 5

(x - 5) (x + 8) = 0

Using the zero factor principle

if ab=0, then a=0 or b=0 (or both a=0 and b=0)

x-5=0\quad \mathrm{or}\quad \:x+8=0

Solve x - 5 = 0

x - 5 = 0

adding 5 to both sides

x - 5 + 5 = 0 + 5

x = 5

solve x + 8 = 0

x + 8 = 0

subtracting 8 from both sides

x + 8 - 8 = 0 - 8

x = -8

Therefore, the roots (zeros) of the function are:

x=5,\:x=-8

6 0
2 years ago
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