Ok so
what we do is
how much greater=wasted space=cylindervolume-conevolume
volume of a cinlinder=hpir^2
volume of a cone=(1/3)hpir^2
we can alread sybsitute something
(3/3)hpir^2-(1/3)hpir^2=(2/3)hpir^2
so wasted space=(2/3)hpir^2
diameter=4
d=2r
d/2=r
4/2=2=r
and 6=height
so
2/3(6)(3.14)(2^2)
4(3.14)(4)
16(3.14)
50.24 in^3 wasted
This triangle is called a 45-45-90 triangle, and the side ratio for the sides opposite to the 45-45-90 degree angles respectively are 1-1-sqrt2
Now we know one side is 6 and its opposing the 45 degrees angle and BC is opposing the 90 degrees angle the ratio between the sides are 1:sqrt2
Therefore BC=6*sqrt2=6sqrt2
Thus B is the correct answer!
Hope this helped any questions just leave them in the comments of this answer.
Answer:
see explanation
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y-intercept )
(a)
here m = -
and c = 6, hence
y = -
x + 6 ← equation of line
(b)
here m = 6, hence
y = 6x + c ← is the partial equation
to find c substitute (2, - 6 ) into the partial equation
- 6 = 12 + c ⇒ c = - 6 - 12 = - 18
y = 6x - 18 ← equation of line
(c)
to calculate m use the gradient formula
m = ( y₂ - y₁ ) / ( x₂ - x₁ )
with (x₁, y₁ ) = (- 1, 3) and (x₂, y₂ ) = (4, 7)
m =
=
, hence
y =
x + c ← is the partial equation
to find c substitute either of the 2 points into the partial equation
using (- 1, 3 ), then
3 = -
+ c → c = 3 +
= 
y =
x +
← equation of line
12 is the answer because you subtract 8 from 20
The first step to solving this problem is to calculate the cube root. The first step to calculating this is to take the root of the fraction and then take the root of both the numerator and denominator separately. This will look like the following:
![\frac{ \sqrt[3]{-64} }{ \sqrt[3]{125} }](https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%5Csqrt%5B3%5D%7B-64%7D%20%7D%7B%20%5Csqrt%5B3%5D%7B125%7D%20%7D%20)
An odd root of a negative radicand is always negative,, so the top of the fraction will need to change to the following:
![\frac{- \sqrt[3]{64} }{ \sqrt[3]{125} }](https://tex.z-dn.net/?f=%20%5Cfrac%7B-%20%5Csqrt%5B3%5D%7B64%7D%20%7D%7B%20%5Csqrt%5B3%5D%7B125%7D%20%7D%20)
For the bottom fraction,, you must write it in exponential form.
![\frac{- \sqrt[3]{64} }{ \sqrt[3]{ 5^{3} } }](https://tex.z-dn.net/?f=%5Cfrac%7B-%20%5Csqrt%5B3%5D%7B64%7D%20%7D%7B%20%5Csqrt%5B3%5D%7B%205%5E%7B3%7D%20%7D%20%7D%20)
Now write the top expression in exponential form
![\frac{- \sqrt[3]{ 4^{3} } }{ \sqrt[3]{ 5^{3} } }](https://tex.z-dn.net/?f=%20%5Cfrac%7B-%20%5Csqrt%5B3%5D%7B%204%5E%7B3%7D%20%7D%20%7D%7B%20%5Csqrt%5B3%5D%7B%205%5E%7B3%7D%20%7D%20%7D%20)
For the bottom of the fraction,, reduce the index of the radical and exponent with 3.
![\frac{ - \sqrt[3]{ 4^{3} } }{5}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%20-%20%5Csqrt%5B3%5D%7B%204%5E%7B3%7D%20%7D%20%7D%7B5%7D%20)
Now reduce the index of the radical and exponent with 3 on the top of the fraction.

Lastly,, use

to rewrite the fraction.

This means that the correct answer to this question is option A.
Let me know if you have any further questions
:)