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2 years ago

Determine the difference

Mathematics

1 answer:

SCORPION-xisa [38]2 years ago

4 0

Answer:

B: 43.3

Step-by-step explanation:

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The temperature at 9 p.m. was 12°F. The temperature dropped 15°F by 5 a.m.The temperature at 5 a.m. was

satela [25.4K]

The temperature at 5 am was -3 degrees

12-15=-3

4 0

2 years ago

Find the value of t needed to make the equation shown true. <br><br> 25t = 12.5

-Dominant- [34]

Answer:

1/2

Step-by-step explanation:

Hi Avahosel2020!

To find the value of $t$ we need to simplify the equation:

25 $t$ = 12.5

To just get $t$ , we must divide 25 on both sides:

$\frac{25t}{25}$ = $\frac{12.5}{25}$

<u>We can move the decimal one spot over and add a 0 to the denominator:</u>

$\frac{25t}{25}$ = $\frac{125}{250}$

$t$ = $\frac{125}{250}$

Simplifying!

$\frac{125}{250}$ = $\frac{1}{2}$ .

Thus, $t$ has the value of $\boxed{\frac{1}{2} }$ .

7 0

2 years ago

(MULTIPLE CHOICE QUESTION)

balu736 [363]

your answer's correct.

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Find the 2th term of the expansion of (a-b)^4.

vladimir1956 [14]

The second term of the expansion is $-4a^3b$ .

Solution:

Given expression:

$(a-b)^4$

To find the second term of the expansion.

$(a-b)^4$

Using Binomial theorem,

$(a+b)^{n}=\sum_{i=0}^{n}\left(\begin{array}{l}n \\i\end{array}\right) a^{(n-i)} b^{i}$

Here, a = a and b = –b

$$(a-b)^4=\sum_{i=0}^{4}\left(\begin{array}{l}4 \\i\end{array}\right) a^{(4-i)}(-b)^{i}$

Substitute i = 0, we get

$$\frac{4 !}{0 !(4-0) !} a^{4}(-b)^{0}=1 \cdot \frac{4 !}{0 !(4-0) !} a^{4}=a^4$

Substitute i = 1, we get

$$\frac{4 !}{1 !(4-1) !} a^{3}(-b)^{1}=\frac{4 !}{3!} a^{3}(-b)=-4 a^{3} b$

Substitute i = 2, we get

$$\frac{4 !}{2 !(4-2) !} a^{2}(-b)^{2}=\frac{12}{2 !} a^{2}(-b)^{2}=6 a^{2} b^{2}$

Substitute i = 3, we get

$$\frac{4 !}{3 !(4-3) !} a^{1}(-b)^{3}=\frac{4}{1 !} a(-b)^{3}=-4 a b^{3}$

Substitute i = 4, we get

$$\frac{4 !}{4 !(4-4) !} a^{0}(-b)^{4}=1 \cdot \frac{(-b)^{4}}{(4-4) !}=b^{4}$

Therefore,

$$(a-b)^4=\sum_{i=0}^{4}\left(\begin{array}{l}4 \\i\end{array}\right) a^{(4-i)}(-b)^{i}$

$=\frac{4 !}{0 !(4-0) !} a^{4}(-b)^{0}+\frac{4 !}{1 !(4-1) !} a^{3}(-b)^{1}+\frac{4 !}{2 !(4-2) !} a^{2}(-b)^{2}+\frac{4 !}{3 !(4-3) !} a^{1}(-b)^{3}+\frac{4 !}{4 !(4-4) !} a^{0}(-b)^{4}$ $=a^{4}-4 a^{3} b+6 a^{2} b^{2}-4 a b^{3}+b^{4}$

Hence the second term of the expansion is $-4a^3b$ .

3 0

2 years ago

T. The entropy change As, for an ideal gas is given by the following formula: dT dV As=1C [c. R T V 7 where T is the thermodynam

MissTica

Answer:

The entropy change AS, for an ideal gas is given by: dt V Where T is the thermodynamic temperature, V is the volume and R=8.314. Determine the entropy change when a gas expands from 1 litre to 3 litres for a temperature rise from 100K to 400K given that: Cv = 45 + 6 x 10-T + 8 x 10-6T2 b) The average value of a complex voltage waveform is given by: V = ( 10 (10sin ox +3sin 30x +2 sin 508) dt Evaluate Vav correct to 2 decimal places.

7 0

2 years ago