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lord [1]
3 years ago
8

Joel had 200 coins, which were dimes and quarters. The total value is $32.

Mathematics
1 answer:
il63 [147K]3 years ago
4 0

Answer:

Joel had 120 dimes and 80 quarters.

Step-by-step explanation:

Given that Joel had 200 coins, which were dimes and quarters, and the total value was $ 32, to determine how many coins of each type he had, the following calculation must be performed:

0.25 - 0.10 = 0.15

200 x 0.10 = 20

32 - 20 = 12

12 / 0.15 = 80

200 - 80 = 120

(80 x 0.25) + (120 x 0.1) = X

20 + 12 = X

32 = X

Thus, Joel had 120 dimes and 80 quarters.

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Answer:

a) Option A)

H_{0}: \mu \geq 1503\\H_A: \mu < 1503

b) Point estimate of difference = -78

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = $1,503

Sample mean, \bar{x} = $1,425

Sample size, n = 25

Sample standard deviation, s = $160

We have to carry a hypothesis test that the mean annual premium in Pennsylvania is lower than the national mean annual premium.

a) First, we design the null and the alternate hypothesis

H_{0}: \mu \geq 1503\text{ dollars}\\H_A: \mu < 1503\text{ dollars}

b) Point estimate  of the difference between the mean annual premium in Pennsylvania and the national mean

Point estimate of difference =

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\text{Point estimate} = \bar{x} - \mu = 1425 - 1503 = -78

Thus,

Point estimate of difference = -78

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