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snow_lady [41]
2 years ago
5

Which of the following is equal to [(x^2y^3)^2/(x^6y^3z)^2]^3

Mathematics
2 answers:
bogdanovich [222]2 years ago
5 0

Answer:

A B D on Edge2020

Nikitich [7]2 years ago
3 0

Answer: Move x32 x 3 2 to the denominator using the negative exponent rule bn=1b−n b n = 1 b - n . ⎛⎝3y3x2y−12x−32⎞⎠−2 ( 3 y 3 x 2 y - 1 2 x - 3 2 ) - 2. Multiply ...

Step-by-step explanation:

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Find the 7th term of the sequence 216,-144,96,-64
MrMuchimi

Answer:

Step-by-step explanation:

r=-144/216=-2/3

a_{7}=216(-2/3)^{7-1}\\=216(\frac{-2}{3} )^6\\\\=216(\frac{2^6}{3^6})\\=216\times\frac{64}{729}\\=\frac{512}{27}\\

3 0
2 years ago
A can of tuna has a shape similar to the shape of a large water take the can of tuna has a diameter of 3 inches and a height of
ankoles [38]
6 yards = 216 inches

make a proportion and cross multiply:

3/216 = 2/x
*cross multiply*
3x = 216(2)

x = 144 inches or 4 yards
5 0
3 years ago
Read 2 more answers
I need a little bit of halp plzzzz!!! a bag of pennies weighs 5.1 kilograms. Each penny weighs 2.5 grams. About how many pennies
Harrizon [31]
Hello!

so we have a total weight of 5.1kg and we are told that each penny weighs 2.5g.

so we need to convert either one to the same units first. we know there are 1000g in 1kg so 2.5g=0.0025kg now we have both in the units of kg, so we can just take 5.1kg/0.0025kg=2040 pennies in the bag. 

we can check ourselves here by taking 2040 * 2.5g and we get 5100grams which equals 5.1kg  

hope this helps. any questions please just ask. thank you kindly
3 0
2 years ago
What is the value of the element at b23 ?
Leya [2.2K]

\qquad\qquad \textit{columns}\\ b=\begin{bmatrix} 6&-5&16\\ 3&22&\boxed{24}\\ 7&22&14 \end{bmatrix} \begin{array}{llll} r\\o\\w\\s \end{array}\qquad \impliedby \qquad \begin{array}{llll} b23\\ \textit{matrix "b"}\\ \textit{row 2}\\ \textit{column 3} \end{array}

4 0
2 years ago
The sum of the first term of an ap is 240 and the sum of the next 4 term is 220 find the first term of the ap
Sindrei [870]

Answer:

The common difference is -5/4

T(n) = T(0)  - 5n/4,

where T(0) can be any number. d = -5/4

Assuming T(0) = 0, then first term

T(1) = 0 -5/4 = -5/4

Step-by-step explanation:

T(n) = T(0) + n*d

Let

S1 = T(x) + T(x+1) + T(x+2) + T(x+3) = 4*T(0) + (x + x+1 + x+2 + x+3)d = 240

S2 = T(x+4) + T(x+5) + T(x+6) + T(x+7) = 4*T(0) + (x+5 + x+6 + x+7 + x+8)d = 220

S2 - S1

= 4*T(0) + (x+5 + x+6 + x+7 + x+8)d - (4*T(0) + (x+1 + x+2 + x+3 + x+4)d)

= (5+6+7+8 - 1 -2-3-4)d

= 4(4)d

= 16d

Since S2=220,  S1 = 240

220-240 = 16d

d = -20/16 = -5/4

Since T(0) has not been defined, it could be any number.

7 0
2 years ago
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