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Mazyrski [523]
3 years ago
12

PLEASE HELP I'M REALLY CONFUSED:(

Mathematics
1 answer:
Stels [109]3 years ago
4 0
-3(x+4)=-6
-3x-12=-6
-3x=6
X=-2
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2 1/3 * 2 1/4 * 1 3/8
Aleks [24]

Answer:

7.21875

Step-by-step explanation:

7 0
3 years ago
PLSSS HELP IF YOU TURLY KNOW THISS
lesantik [10]

Answer:

x=4 hope this helps

Step-by-step explanation:

3 0
2 years ago
The school is 3.2 blocks from someone’s house. how many blocks does the person walk to go to and from school?
DENIUS [597]

The answer is: " 6.4 blocks " .

________________________________________________________

3.2 blocks (one way), PLUS: 3.2 blocks the other way:

3.2 + 3.2 = 6.4 blocks .

or: (3.2) * 2 = 6.4 blocks .

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The answer is: " 6.4 blocks " .

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4 0
3 years ago
1) Use power series to find the series solution to the differential equation y'+2y = 0 PLEASE SHOW ALL YOUR WORK, OR RISK LOSING
iogann1982 [59]

If

y=\displaystyle\sum_{n=0}^\infty a_nx^n

then

y'=\displaystyle\sum_{n=1}^\infty na_nx^{n-1}=\sum_{n=0}^\infty(n+1)a_{n+1}x^n

The ODE in terms of these series is

\displaystyle\sum_{n=0}^\infty(n+1)a_{n+1}x^n+2\sum_{n=0}^\infty a_nx^n=0

\displaystyle\sum_{n=0}^\infty\bigg(a_{n+1}+2a_n\bigg)x^n=0

\implies\begin{cases}a_0=y(0)\\(n+1)a_{n+1}=-2a_n&\text{for }n\ge0\end{cases}

We can solve the recurrence exactly by substitution:

a_{n+1}=-\dfrac2{n+1}a_n=\dfrac{2^2}{(n+1)n}a_{n-1}=-\dfrac{2^3}{(n+1)n(n-1)}a_{n-2}=\cdots=\dfrac{(-2)^{n+1}}{(n+1)!}a_0

\implies a_n=\dfrac{(-2)^n}{n!}a_0

So the ODE has solution

y(x)=\displaystyle a_0\sum_{n=0}^\infty\frac{(-2x)^n}{n!}

which you may recognize as the power series of the exponential function. Then

\boxed{y(x)=a_0e^{-2x}}

7 0
3 years ago
WILL GIVE BRAINLIEST!!!​
Dahasolnce [82]

Answer:

(3/4)*x

Step-by-step explanation:

Dilation really means  the multiply the scale factor  to every segment of the original figure or shape to get the new transformed figure.

so  (3/4) * (segment lengths) = (new segment lengths)

5 0
3 years ago
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