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Hunter-Best [27]
3 years ago
15

X^{2}-7x-25=0 to the nearest tenth

Mathematics
2 answers:
shepuryov [24]3 years ago
5 0

Answer:

x = 9.6

x = - 2.6

Step-by-step explanation:

x=\frac{-b±\sqrt{b^{2}-4ac } }{2a}

Ignore the before the ± it wouldn't let me type it correctly.

x² - 7x - 25 = 0

a = 1

b = - 7

c = - 25

x=\frac{-(-7)±\sqrt{-7^{2}-4((1)(-25)) } }{2(1)}

x=\frac{7±\sqrt{49-4((1)(-25)) } }{2(1)}

x=\frac{7±\sqrt{49+100 } }{2(1)}

x=\frac{7±\sqrt{149 } }{2}

x=\frac{7±12.2}{2}

Two separate equations

x=\frac{7+12.2}{2}

x=\frac{7-12.2}{2}

x=\frac{7+12.2}{2}

x=\frac{19.2}{2}

x = 9.6

x=\frac{7-12.2}{2}

x=\frac{-5.2}{2}

x = - 2.6

Verdich [7]3 years ago
5 0

For this just use the quadratic formula to find the zeros. In this case, you get 7 +/- square root 149 over 2. Which gives you -2.6 and 9.6.

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