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Hunter-Best [27]
3 years ago
15

X^{2}-7x-25=0 to the nearest tenth

Mathematics
2 answers:
shepuryov [24]3 years ago
5 0

Answer:

x = 9.6

x = - 2.6

Step-by-step explanation:

x=\frac{-b±\sqrt{b^{2}-4ac } }{2a}

Ignore the before the ± it wouldn't let me type it correctly.

x² - 7x - 25 = 0

a = 1

b = - 7

c = - 25

x=\frac{-(-7)±\sqrt{-7^{2}-4((1)(-25)) } }{2(1)}

x=\frac{7±\sqrt{49-4((1)(-25)) } }{2(1)}

x=\frac{7±\sqrt{49+100 } }{2(1)}

x=\frac{7±\sqrt{149 } }{2}

x=\frac{7±12.2}{2}

Two separate equations

x=\frac{7+12.2}{2}

x=\frac{7-12.2}{2}

x=\frac{7+12.2}{2}

x=\frac{19.2}{2}

x = 9.6

x=\frac{7-12.2}{2}

x=\frac{-5.2}{2}

x = - 2.6

Verdich [7]3 years ago
5 0

For this just use the quadratic formula to find the zeros. In this case, you get 7 +/- square root 149 over 2. Which gives you -2.6 and 9.6.

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8 0
4 years ago
Read 2 more answers
One of the tallest buildings in a country is topped by a high antenna. The angle of elevation from the position of a surveyor on
irina1246 [14]

Answer:

a. distance of the surveyor to the base of the building = 2051.90 ft

b. height of the building = 1384 ft

c. Angle of elevation from the surveyor to the top of the antenna = 38.31°

d. Height of antenna  =  237.08 ft

Step-by-step explanation:

​The picture above is a illustration of the described event.

a = the height of the flag

b = the height of the building

c = distance of the surveyor from the base of the building

the angle of elevation from the position of the surveyor on the ground to the top of the building = 34°  

distance from her position to the top of the building  = 2475 ft

distance from her position to the top of the flag  = 2615 ft

​(a) How far away from the base of the building is the surveyor​ located?​

using the SOHCAHTOA principle

cos 34° = c/2475

c =  0.8290375726  × 2475

c = 2051.8679921

c = 2051.90 ft

(b) How tall is the​ building

The height of the building = b

sin 34° = opposite /hypotenuse

0.5591929035 = b/2475

b =  0.5591929035  × 2475

b =  1384.0024361

b =  1384.00 ft

​(c) What is the angle of elevation from the surveyor to the top of the​ antenna?

let the angle = ∅

cos ∅ = adjacent/hypotenuse

cos ∅ = 2051.90/2615

cos ∅ =  0.784665392

∅ = cos-1  0.784665392

∅ =   38.310258303

∅ =  38.31°

​(d) How tall is the​ antenna?

height of the antenna = a

sin 38.31° = opposite/hypotenuse

sin 38.31° = (a + b)/2615

sin 38.31° × 2615 = (a + b)

(a + b) =  0.6199159917  × 2615

(a + b) =  1621.0803182

(a + b) = 1621. 08 ft

Height of antenna = 1621. 08 - 1384.00  =  237.08031822 ft

Height of antenna  =  237.08 ft

8 0
3 years ago
Fing the value of x, -3(2x-9)=3(16-x)
Ksivusya [100]

Answer:

x= -7

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Multiply: (4x – 7)(2x – 9)
Marizza181 [45]
Hello there!


Let's use foil.

First: 4x * 2x = 8x^2

Outside: 4x * -9 = -36x

Inside: -7 * 2x = -14x

Last: -7 * -9 = 63


Now, let's combine these.

8x^2 - 36x - 14x + 63

Finally, we can simplify this

8x - 50x + 63



I hope I helped!

Let me know if you need anything else!

~ Zoe


7 0
3 years ago
Pic attached for further detail
marissa [1.9K]
I dont get what you asking
8 0
3 years ago
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